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Sir Mathematics BlogThis a blog for posting and commenting on things math related.
http://sirmathematicstutoringblog.blogspot.com/
This a blog for posting and commenting on things math related.
http://sirmathematicstutoringblog.blogspot.com/
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https://sirmathematicstutoringblog.blogspot.com
This a blog for posting and commenting on things math related.
sirmathematicstutoringblog.blogspot.com
Sir Mathematics Blog: Understanding Equations
http://sirmathematicstutoringblog.blogspot.com/2011/03/understanding-equations.html
This a blog for posting and commenting on things math related. Thursday, March 17, 2011. Equations are all about working with equality. As with our last blog, we will use an example involving money. If you had $50 and then spent $50 dollars you would have $0. Right? Now let's say Bob has some money, he spent $50 dollars and now he no longer has any money. How much money did Bob have? Which simplifies to tell us;. Which of course we already knew from before. 3L 139 = 160. So 3 lunches plus the Kindle has ...
Sir Mathematics Blog: Student Getting Help From a Sibling
http://sirmathematicstutoringblog.blogspot.com/2012/04/student-getting-help-from-sibling.html
This a blog for posting and commenting on things math related. Saturday, April 14, 2012. Student Getting Help From a Sibling. An eager math student wanted to move ahead in class and started working on topics the instructor had not covered yet. The student came across 5! And did not know what to do, so the student asked an older brother what 5! Meant The older brother's response is in the following video clip. Posted by Sir Mathematics. April 14, 2012 at 7:42 PM. Thats what older brothers are for.
Sir Mathematics Blog: April 2012
http://sirmathematicstutoringblog.blogspot.com/2012_04_01_archive.html
This a blog for posting and commenting on things math related. Monday, April 23, 2012. I don't remember the entire question but here is the info I remember; for the sequence every term except for the first term is found by multiplying the previous term by 3 and subtracting by 1 and the difference between the 5th term and 3rd term is 28. Find the value of the first term of the sequence. 3(4th)-1-3(2nd) 1=28 or rather 3(4th)-3(2nd)=28. Now factor out the 3, so you have 3(4th-2nd)=28. Start with 1;. Each on...
Sir Mathematics Blog: March 2011
http://sirmathematicstutoringblog.blogspot.com/2011_03_01_archive.html
This a blog for posting and commenting on things math related. Thursday, March 17, 2011. Equations are all about working with equality. As with our last blog, we will use an example involving money. If you had $50 and then spent $50 dollars you would have $0. Right? Now let's say Bob has some money, he spent $50 dollars and now he no longer has any money. How much money did Bob have? Which simplifies to tell us;. Which of course we already knew from before. 3L 139 = 160. So 3 lunches plus the Kindle has ...
Sir Mathematics Blog
http://sirmathematicstutoringblog.blogspot.com/2012/04/i-dont-remember-entire-question-but.html
This a blog for posting and commenting on things math related. Monday, April 23, 2012. I don't remember the entire question but here is the info I remember; for the sequence every term except for the first term is found by multiplying the previous term by 3 and subtracting by 1 and the difference between the 5th term and 3rd term is 28. Find the value of the first term of the sequence. 3(4th)-1-3(2nd) 1=28 or rather 3(4th)-3(2nd)=28. Now factor out the 3, so you have 3(4th-2nd)=28. Start with 1;. Each on...
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Sir Math Tel 347-460-MATH (6284). Tutors schedule fall 2014.pdf. Math 120 Q21 Review for Exam 2. P1 = (2,2) p2= (-11,-8). Slope formula (y2-y1)/ (x2-x1) - (10/13) = m. Then use (y-y1)=m(x-x1) easiest point (2,2) = (x1,y1). Step 1 - (y-2)= (10/13)(x-2). Step 2 - (y-2)= 10/13x-(20/13). Step 3 - y= 10/13x-(20/13) 2. Step 4 - y= 10/13x-(20/13) 2 (13/13). Step 5 - y= 10/13x-(20/13) (26/13). Step 6 - y=10/13x (6/13) = Answer. Math 119 how to graph a linear line. How to make a bacis line in mathematica.
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This a blog for posting and commenting on things math related. Monday, April 23, 2012. I don't remember the entire question but here is the info I remember; for the sequence every term except for the first term is found by multiplying the previous term by 3 and subtracting by 1 and the difference between the 5th term and 3rd term is 28. Find the value of the first term of the sequence. 3(4th)-1-3(2nd) 1=28 or rather 3(4th)-3(2nd)=28. Now factor out the 3, so you have 3(4th-2nd)=28. Start with 1;. Each on...
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