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Project Euler

Monday, August 15, 2011. Num ending in 89. Num ending in 89. Num ending in 89. Syntax highlighted by Code2HTML. Posted by Ben Andken. Consider the following magic 3-gon ring, filled with the numbers 1 to 6, and each line adding to nine. Working clockwise, and starting from the group of three with the numerically lowest external node (4,3,2 in this example), each solution can be described uniquely. For example, the above solution can be described by the set: 4,3,2; 6,2,1; 5,1,3. Printf(%d%c, *i, i 1!

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Project Euler | benprojecteuler.blogspot.com Reviews

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Monday, August 15, 2011. Num ending in 89. Num ending in 89. Num ending in 89. Syntax highlighted by Code2HTML. Posted by Ben Andken. Consider the following magic 3-gon ring, filled with the numbers 1 to 6, and each line adding to nine. Working clockwise, and starting from the group of three with the numerically lowest external node (4,3,2 in this example), each solution can be described uniquely. For example, the above solution can be described by the set: 4,3,2; 6,2,1; 5,1,3. Printf(%d%c, *i, i 1!

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6 using

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Project Euler | benprojecteuler.blogspot.com Reviews

https://benprojecteuler.blogspot.com

Monday, August 15, 2011. Num ending in 89. Num ending in 89. Num ending in 89. Syntax highlighted by Code2HTML. Posted by Ben Andken. Consider the following magic 3-gon ring, filled with the numbers 1 to 6, and each line adding to nine. Working clockwise, and starting from the group of three with the numerically lowest external node (4,3,2 in this example), each solution can be described uniquely. For example, the above solution can be described by the set: 4,3,2; 6,2,1; 5,1,3. Printf(%d%c, *i, i 1!

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Project Euler: Problem 55

http://benprojecteuler.blogspot.com/2011/08/problem-55_15.html

Monday, August 15, 2011. NOTE: Wording was modified slightly on 24 April 2007 to emphasise the theoretical nature of Lychrel numbers. reverseNumber n = (read(reverse(show n) : Integer) isPalindromic n = n= (reverseNumber n) reverseAdd 0 = [] reverseAdd n = [n] reverseAdd(n (reverseNumber n) isLychrel n = not (foldr False (map (isPalindromic) (take 50 (tail(reverseAdd n) ) ) answer = length(filter isLychrel [1.10000]). Syntax highlighted by Code2HTML. Posted by Ben Andken. View my complete profile.

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Project Euler: August 2011

http://benprojecteuler.blogspot.com/2011_08_01_archive.html

Monday, August 15, 2011. Num ending in 89. Num ending in 89. Num ending in 89. Syntax highlighted by Code2HTML. Posted by Ben Andken. Consider the following magic 3-gon ring, filled with the numbers 1 to 6, and each line adding to nine. Working clockwise, and starting from the group of three with the numerically lowest external node (4,3,2 in this example), each solution can be described uniquely. For example, the above solution can be described by the set: 4,3,2; 6,2,1; 5,1,3. Printf(%d%c, *i, i 1!

3

Project Euler: Problem 51

http://benprojecteuler.blogspot.com/2011/08/problem-51_15.html

Monday, August 15, 2011. By replacing the 1st digit of *3, it turns out that six of the nine possible values: 13, 23, 43, 53, 73, and 83, are all prime. By replacing the 3rd and 4th digits of 56* 3 with the same digit, this 5-digit number is the first example having seven primes among the ten generated numbers, yielding the family: 56003, 56113, 56333, 56443, 56663, 56773, and 56993. Consequently 56003, being the first member of this family, is the smallest prime with this property. Posted by Ben Andken.

4

Project Euler: Problem 54

http://benprojecteuler.blogspot.com/2011/08/problem-54_15.html

Monday, August 15, 2011. FILE, poker.txt. Can't open poker.txt. FILE ; foreach. Print n n . $ . n;. Check for straight flush. Check for straight flush. 1 = $sorted numbers. 1 = $sorted numbers. 1 = $sorted numbers. 1 = $sorted numbers. 14 & $sorted numbers. 2 & $sorted numbers. 3 & $sorted numbers. 4 & $sorted numbers. ERROR straightRank order 0. 14 & $sorted numbers. ERROR flushRank order 0. ERROR threeOfAKindRank order 0. The middle one will be the correct one. ERROR twoPairRank order 2.

5

Project Euler: Problem 50

http://benprojecteuler.blogspot.com/2011/08/problem-50_15.html

Monday, August 15, 2011. The prime 41, can be written as the sum of six consecutive primes:. 41 = 2 3 5 7 11 13. This is the longest sum of consecutive primes that adds to a prime below one-hundred. The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953. Which prime, below one-million, can be written as the sum of the most consecutive primes? Current max: %d . ans: %d n. Syntax highlighted by Code2HTML. Posted by Ben Andken.

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The Education of Ben: August 2011

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The Education of Ben. This blog is set up as a portfolio of the projects that I've worked on over the past 10 years. A lot of them I no longer have the dates when I originally worked on them, but I included them anyway. It's mostly so I can share them with others, so if there's a better way to share it, let me know. Monday, August 29, 2011. Fixing an electric piano. The interval is 5 seconds per picture, and there are 1200 images. That's roughly 1.5 hours over two days. Fixing an MP 300. I've always been...

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Project Euler

Monday, August 15, 2011. Num ending in 89. Num ending in 89. Num ending in 89. Syntax highlighted by Code2HTML. Posted by Ben Andken. Consider the following magic 3-gon ring, filled with the numbers 1 to 6, and each line adding to nine. Working clockwise, and starting from the group of three with the numerically lowest external node (4,3,2 in this example), each solution can be described uniquely. For example, the above solution can be described by the set: 4,3,2; 6,2,1; 5,1,3. Printf(%d%c, *i, i 1!

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