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An online judge paltform for learning and judging c/c++/java/pascal program.

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An online judge paltform for learning and judging c/c++/java/pascal program.
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10 其实没有什么好说的,就分解成循环求长度的最小公倍数就好了
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navigation switch,rating,contests,hdoj,register,times;,pending,ended,provider dwjshiftfan2,其实没有什么好说的,就分解成循环求长度的最小公倍数就好了,注意判断特殊情形,no1 doubility,不好意思,本场题意bug太多,出题人给大家道歉了,本题唯一一个值得注意的点就是当n接近60时会爆int,每次更新时更新高度即可,在pushup过程中去计算新产生的 高山脉,然后对于一个询问,具体的更新过程是 每次更新一个点
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An online judge paltform for learning and judging c/c++/java/pascal program.

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Rating - dwjshiftfan2

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Select to zoom in, hold. Swipe to show more. BestCoder Contest System 2.0.

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Contest Problem List

http://bestcoder.acmcoder.com/contests/contest_show.php?cid=620

The contest ended, you can see Ranklist. BestCoder Round #52 (div.1) ($). 2015-08-22 19:00:00 - 2015-08-22 21:00:00 Current Time:. BestCoder Contest System 2.0.

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BestCoder Solution

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1001 Fxx and string 枚举$ :i :$和等比数列公比$ :q :$,但考虑到$ :q :$有可能是$ :1/t :$的形式,所以倒过来枚举一遍就可以了。 1002 Fxx and game 设$ :F i :$表示将$ :i :$变为$ :1 :$的最少步骤,如果$ :k i,F i=min {F j,F { frac{i}{k} }$,否则$ :F i=min {F j }$,其中$ :i-t leq j leq i-1$。 1003 Fxx and tree 考虑从上往下贪心,要将整棵树翻白,有唯一的方案。 设$ :f x :$表示还有$ :n-x :$个正确的点没有翻需要的期望步数。 F 0=f 1 1,f i= frac{i}{n}f {i-1} frac{n-i}{n}f {i 1} 1,f n=0$ 用高斯消元求出解就行了。 由第一类斯特林数可以证明当$ :3 :$操作无限时,环的数量是$ :log(n) :$级别的。 又由于$ :3 :$操作数量对于$ :n :$的数量是很大的且数据随机,所以我们可以得到在本题中环的数量是$ :log :$级别的。 先给大家道个歉, 验...

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BestCoder Round #52 (div.1) ($). BestCoder Round #52 (div.2). BestCoder Round #51 (div.1) ($). 本场题意出现了一些问题.在此向大家道歉. # 1000 Zball in Tina Town 出题人:wuzhuangtai00 这题就是求 $(n-1)! Mod n$ 如果$n$为合数,显然答案为0. 如果$n$为素数,那么由威尔逊定理可得答案为 $n-1$ 注意有个trick为 $n$ = 4. # 1001 Infoplane in Tina Town 出题人:zball 给出一个置换,求它的循环长度。 数据范围 $3 times 10 6$。 将$( k-1)x 0 b)/(k-1)p$约分,令分母为$q=(k-1)p/d$。 下面即要求解$k n equiv 1 mod q$。 注意到若$q 10 9 9$,则我们可以很容易地得到一个不大于$10 9 9$的因子,接下来只需要将$q$拆成两部分分别质因子分解即可。 1003 Trie in Tina Town 出题人:zball 我们可以先假设给出的是一个...

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Hi BestCoder

BestCoder Round #52 (div.1) ($). BestCoder Round #52 (div.2). BestCoder Round #51 (div.1) ($). 本场题意出现了一些问题.在此向大家道歉. # 1000 Zball in Tina Town 出题人:wuzhuangtai00 这题就是求 $(n-1)! Mod n$ 如果$n$为合数,显然答案为0. 如果$n$为素数,那么由威尔逊定理可得答案为 $n-1$ 注意有个trick为 $n$ = 4. # 1001 Infoplane in Tina Town 出题人:zball 给出一个置换,求它的循环长度。 数据范围 $3 times 10 6$。 将$( k-1)x 0 b)/(k-1)p$约分,令分母为$q=(k-1)p/d$。 下面即要求解$k n equiv 1 mod q$。 注意到若$q 10 9 9$,则我们可以很容易地得到一个不大于$10 9 9$的因子,接下来只需要将$q$拆成两部分分别质因子分解即可。 1003 Trie in Tina Town 出题人:zball 我们可以先假设给出的是一个...

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