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Bytes of the day | A CS byte per day

A CS byte per day

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Bytes of the day | A CS byte per day | bytesoftheday.wordpress.com Reviews

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A CS byte per day

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bytesoftheday | Bytes of the day

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Bytes of the day. A CS byte per day. Q171: Solution to Critical Section Problem. February 16, 2015. February 16, 2015. Does the following solution solve the critical section problem? While(true) { while (flag); / Spin lock flag = true; / critical section flag = false; / remainder section }. No, there should be ‘if’ condition instead of ‘while’. Yes, it solves the problem. Posted in Embedded Systems. Q170: Total no. of ways to climb n stairs (one or two at a time). February 11, 2015. If a person can climb...

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Q169: What is the maximum number of inversions possible? | Bytes of the day

https://bytesoftheday.wordpress.com/2015/02/10/q169

Bytes of the day. A CS byte per day. Q169: What is the maximum number of inversions possible? February 10, 2015. In continuation with Question 168. What is the maximum number of inversions possible in a sequence of ‘N’ numbers? The correct answer is option 3. There are total C(N, 2) pairs possible when all of the numbers are inverted. Following is an example for the same:. Q168: How many no. of inversions exist in the following sequence? Q170: Total no. of ways to climb n stairs (one or two at a time).

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Q171: Solution to Critical Section Problem | Bytes of the day

https://bytesoftheday.wordpress.com/2015/02/16/q171-solution-to-critical-section-problem

Bytes of the day. A CS byte per day. Q171: Solution to Critical Section Problem. February 16, 2015. February 16, 2015. Does the following solution solve the critical section problem? While(true) { while (flag); / Spin lock flag = true; / critical section flag = false; / remainder section }. No, there should be ‘if’ condition instead of ‘while’. Yes, it solves the problem. Posted in Embedded Systems. Q170: Total no. of ways to climb n stairs (one or two at a time). Leave a Reply Cancel reply. You are comm...

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Q170: Total no. of ways to climb n stairs (one or two at a time) | Bytes of the day

https://bytesoftheday.wordpress.com/2015/02/11/q170

Bytes of the day. A CS byte per day. Q170: Total no. of ways to climb n stairs (one or two at a time). February 11, 2015. If a person can climb either one stair at a time or 2 stairs at a time, then how many total no. of ways will be there to climb 5 stairs? F(n) = f(n-1) f(n-2). Hence, f(5) can be calculated as:. F(5) = f(4) f(3). F(5) = f(3) f(2) f(2) f(1). F(5) = f(2) f(1) f(2) f(2) f(1). Hence, f(5) will be 8 based on the above equation. Hence the correct answer is option 4. Leave a Reply Cancel reply.

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Archives | Bytes of the day

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Bytes of the day. A CS byte per day. Q171: Solution to Critical Section Problem. Q170: Total no. of ways to climb n stairs (one or two at a time). Q169: What is the maximum number of inversions possible? Q168: How many no. of inversions exist in the following sequence? Q167: What happens to shortest paths when we tweak the graph edges. Q166: Second chance page replacement policy. Q165: Encoding of a TM. Q164: Page faults using FIFO page replacement policy. Q163: Concurrent Threads Contd. Q138: Simulate k...

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OS | GATECSE – Hyperbook

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GATECSE – Hyperbook. Gateway to Computer Science Education. The Operating System is responsible for the following functions. 1) scheduler (time allocation to programs) ,. 2) memory manager (space allocation to programs). 3) synchronizer ( avoid conflicts for a resource at the same time). 4)  protection (avoid conflicts for memory). Http:/ www.iu.hio.no/ mark/os/. Quick Intro to various topics. Http:/ elsoc.wikia.com/wiki/Scheduling. Http:/ elsoc.wikia.com/wiki/Concurrency And Synchronization. 2) No proce...

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Bytes of the day | A CS byte per day

Bytes of the day. A CS byte per day. Q171: Solution to Critical Section Problem. February 16, 2015. February 16, 2015. Does the following solution solve the critical section problem? While(true) { while (flag); / Spin lock flag = true; / critical section flag = false; / remainder section }. No, there should be ‘if’ condition instead of ‘while’. Yes, it solves the problem. Posted in Embedded Systems. Q170: Total no. of ways to climb n stairs (one or two at a time). February 11, 2015. If a person can climb...

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