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Coding Beans

Coding如此多嬌, 引無數Geek競折腰。

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Coding Beans | codingbeans.blogspot.com Reviews
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Coding如此多嬌, 引無數Geek競折腰。
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1 coding beans
2 原題連結
3 閱讀更多
4 張貼者:
5 以電子郵件傳送這篇文章
6 blogthis!
7 分享至 twitter
8 分享至 facebook
9 分享到 pinterest
10 data structure
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coding beans,原題連結,閱讀更多,張貼者:,以電子郵件傳送這篇文章,blogthis!,分享至 twitter,分享至 facebook,分享到 pinterest,data structure,enumeration,monotonous,persistent,tioj,day2當中最簡單,也是我唯一有想到的一題orz,沒有留言,construct,math,題目本身並不複雜,這邊簡單的說一下,標籤: connectivity,graph,greedy,這道題個人覺得比較傳統的數學分析
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Coding Beans | codingbeans.blogspot.com Reviews

https://codingbeans.blogspot.com

Coding如此多嬌, 引無數Geek競折腰。

INTERNAL PAGES

codingbeans.blogspot.com codingbeans.blogspot.com
1

Coding Beans: 三月 2016

http://codingbeans.blogspot.com/2016_03_01_archive.html

Coding如此多嬌, 引無數Geek競折腰。 TIOJ 1884][IOI 2015] Boxes. 標籤: algorithm model. Codechef IOPC16Q][Math] Bat In Cage. 標籤: algorithm model. 莫隊算法(Mos algorithm)這幾年非常的紅啊~~. 有很多需要複雜資料結構(LCT , 樹鏈剖分 , 持久化資料結構.) 的題目都可以用莫隊搭配樹壓平之類的技巧作到帶根號的複雜度。 標籤: algorithm model. 2013-2014 Samara SAU ACM ICPC Quarterfinal Qualification Contest pK][BIT][sqrt method] Three Contests. You can view the official tutorial here. This is a simple but interesting data structure problem. Wunder Fund Round 2016 pD][DP] Hamiltonian Spanning Tree.

2

Coding Beans: [TIOJ 1897][IOI 2014] Gondola

http://codingbeans.blogspot.com/2016/04/tioj-1897ioi-2014-gondola.html

Coding如此多嬌, 引無數Geek競折腰。 TIOJ 1897][IOI 2014] Gondola. 這道題分成3個任務:判斷序列合法性,給出任一故障序列,計算故障序列個數,難度也是依序增加的。 但是在這個序列當中如果有某個 =n的數字,也就是從沒有壞過的車子,我們就可以藉著他的位置去確定整個觀看序列所對應的車子編號。 還有一些需要判斷的東西(編號重複,所有車都壞過的case.)都並不難想,就不多說了。 要給出任一故障序列,我們需要先將觀看序列用上面的方法定序(若所有車都壞過不妨隨意定序),這樣我們就可以得到有壞掉的位置是哪些以及他們最後分別是哪幾台車。 然後按照壞掉的編號從小到大排序,把位置編號依序填入崩壞序列即可。(細節可以看code). 我們會發現上面在填入位置編號的過程中,我們直接把「曾經出現但最後沒出現」的新纜車丟給當前處理的位置編號,其實真正的情況是「所有有壞過的位置編號都可以」。 LL fast pow (. 標籤: algorithm model. 訂閱: 張貼留言 (Atom). 教學][String][Data Structure] 後綴自動機(Suffix Automaton).

3

Coding Beans: [Uva 1106][DP] Machine Works

http://codingbeans.blogspot.com/2016/02/uva-1106dp-machine-works.html

Coding如此多嬌, 引無數Geek競折腰。 Uva 1106][DP] Machine Works. 則dp[i]=max( t i-t j-1)*g j r j-p j dp[j]),0 =j i & dp[j] =p j (也有其他表示法,大同小異). Dp[i]=max(g j*t i (r j-p j dp[j]-(t j 1)*g j) ,0 =j i & dp[j] =p j. 因為沒有單調性所以只能用平衡樹來維護凸包線,並且手動實做查詢最大值,插入直線,刪除直線。 不過我們想要在插入直線的同時往左右檢查是否讓某些直線從凸包上消失,我們需要像STL的set: iterator一樣可以作到 ,- 之類對應到序列上的操作。 然後採用的是STL的set包Line,但是這樣要怎麼二分搜呢?只好再多存一個set Point 了!用DB x,y把點表示出來,然後在維護直線的時候同時維護點。 寫完debug完之後過了範測和自產小測資,這樣就可以AC了!.嗎? 因為原題的數值都可以到10 9,一個不小心浮點數誤差就會讓你刪錯點! LL slope ,. Line L1 ,. Line L1 ,.

4

Coding Beans: [HDU 4605][Segment Tree] Magic Ball Game

http://codingbeans.blogspot.com/2016/03/hdu-4605segment-tree-magic-ball-game.html

Coding如此多嬌, 引無數Geek競折腰。 HDU 4605][Segment Tree] Magic Ball Game. 先不管樹這個型態,我們想要查詢的東西其實是「在一堆數字裡有幾個比我小(大)」,這讓我們想到權值線段樹或是Treap,這題兩種應該都是可以的,以下採用權值線段樹。 那麼我們來解決如何對樹的型態做處理。這題關鍵的東西是「從某點到根的路徑」,我們的目標就是要快速找出上面提到的「一堆數字」是哪些數字。 12300;從某點到根的路徑」一開始讓我想到了樹鏈剖分,可以在logn的時間裡獲得「一堆數字」,再花logn的時間去做剛剛提到的查詢;我看了一下原題的記憶體限制和時限,認為這方法實在有點不靠譜.如果有用這個方法做出來的人請務必跟我說XD,順帶一提,這樣做的好處是完全在線回答所有詢問。 時間複雜度:O(nlogc Qlogc),c是值域。 如果有離散化,logc可以壓成logn,也可以簡單的用BIT去做。 標籤: copy on write. 訂閱: 張貼留言 (Atom). Wunder Fund Round 2016 pD][DP] Hamiltonian Spanning Tree.

5

Coding Beans: [Wunder Fund Round 2016 pD][DP] Hamiltonian Spanning Tree

http://codingbeans.blogspot.com/2016/03/wunder-fund-round-2016-pddp-hamiltonian.html

Coding如此多嬌, 引無數Geek競折腰。 Wunder Fund Round 2016 pD][DP] Hamiltonian Spanning Tree. You can view official tutorial here. Here I will explain some points I consider important when trying to solve the problem. There may be some mistakes in grammar due to my poor English QAQ. Any correction of algorithm or grammar is welcomed. It's not hard to find that x y and x y are two different problem: One is to use more tree edges as possible while the other is to use less tree edges. Here's the conclusion for x y :.

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Coding Beans

Coding如此多嬌, 引無數Geek競折腰。 TIOJ 1899][IOI 2014] Holiday. 這道題我一開始以為可以用枚舉和dp去寫,但是複雜度怎麼壓都壓不下來.最後是聽了大神同學的提示才發現我枚舉錯東西了.枚舉天數去做合併大概是沒救的. 標籤: copy on write. TIOJ 1897][IOI 2014] Gondola. 標籤: algorithm model. TIOJ 1895][IOI 2014] Wall. 標籤: data structure. TIOJ 1896][IOI 2014] Game. 這道題目的思維還是有點難度的,但是code寫起來非常精簡,官方提供的構造解法甚至hasEdge裡只須要寫1行.有興趣的可以到IOI2014網站去膜拜一下。 TIOJ 1884][IOI 2015] Boxes. 標籤: algorithm model. Codechef IOPC16Q][Math] Bat In Cage. 標籤: algorithm model. 莫隊算法(Mos algorithm)這幾年非常的紅啊~~. 訂閱: 文章 (Atom). Link Yo...

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