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Programming , Algorithms and Random Stuffs

Programming , Algorithms and Random Stuffs. Saturday, May 6, 2017. Given a root of the binary tree and nodes n1 and n2. Find the lowest common ancestor of the nodes. The lowest common ancestor for D and E in the above tree is C. The least common ancestor for D and B is A. Lowest common ancestor with parent pointer. Here is the code:. Node *lca parent(Node *n1, Node *n2) { Node *t1 = n1, *t2 = n2; int c1 = 0, c2 =0; / Find the distance to the root for n1 while(t1! N2) { res = false; } return res l r; }.

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Programming , Algorithms and Random Stuffs | codinggeeks.blogspot.com Reviews

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Programming , Algorithms and Random Stuffs. Saturday, May 6, 2017. Given a root of the binary tree and nodes n1 and n2. Find the lowest common ancestor of the nodes. The lowest common ancestor for D and E in the above tree is C. The least common ancestor for D and B is A. Lowest common ancestor with parent pointer. Here is the code:. Node *lca parent(Node *n1, Node *n2) { Node *t1 = n1, *t2 = n2; int c1 = 0, c2 =0; / Find the distance to the root for n1 while(t1! N2) { res = false; } return res l r; }.

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Programming , Algorithms and Random Stuffs | codinggeeks.blogspot.com Reviews

https://codinggeeks.blogspot.com

Programming , Algorithms and Random Stuffs. Saturday, May 6, 2017. Given a root of the binary tree and nodes n1 and n2. Find the lowest common ancestor of the nodes. The lowest common ancestor for D and E in the above tree is C. The least common ancestor for D and B is A. Lowest common ancestor with parent pointer. Here is the code:. Node *lca parent(Node *n1, Node *n2) { Node *t1 = n1, *t2 = n2; int c1 = 0, c2 =0; / Find the distance to the root for n1 while(t1! N2) { res = false; } return res l r; }.

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Programming , Algorithms and Random Stuffs: Number base conversion and arithmetic

http://codinggeeks.blogspot.com/2010/05/number-base-conversion-and-arithmetic.html

Programming , Algorithms and Random Stuffs. Wednesday, May 26, 2010. Number base conversion and arithmetic. Perhaps most of us came across base conversions when we were in high school. It's pretty easy to convert numbers from and to decimal if we remember 2 simple rules. If we desire to convert from/to base b to/from decimal we can use following rules:. Conversion from decimal to base b. Num be the given decimal number. Digit[i] = (num /b (i 1) % b. Conversion from base b to decimal.

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Programming , Algorithms and Random Stuffs: Median and Order statistics

http://codinggeeks.blogspot.com/2013/09/median-and-order-statistics.html

Programming , Algorithms and Random Stuffs. Saturday, September 21, 2013. Median and Order statistics. Finding kth median in linear time. Here is the code that implements the above algorithm. Here are some of the questions that are similar to the above question:. Given an algorithm that finds median in linear time. How would you find kth element? Given a set of elements divide the set into k equal parts. Subscribe to: Post Comments (Atom). View my complete profile. Median and Order statistics.

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Programming , Algorithms and Random Stuffs: June 2010

http://codinggeeks.blogspot.com/2010_06_01_archive.html

Programming , Algorithms and Random Stuffs. Monday, June 7, 2010. Conversion from infix to postfix. Returns true if stk precedes infix. Bool precedes(char stk, char infix) {. Declare an array of operators in precedence order. Considers only 4 operators now. Static char prec[] ={'/','*',' ','-'};. For(int i = 0; i. Std: string postfix(const std: string &infix) {. Std: stack char op stack;. Std: string post fix;. If it is a digit add it to postfix. Post fix.append(1,infix[i]);. The post fix string.

4

Programming , Algorithms and Random Stuffs: Singleton in Java the 1.5 way

http://codinggeeks.blogspot.com/2010/05/singleton-in-java-15-way.html

Programming , Algorithms and Random Stuffs. Monday, May 31, 2010. Singleton in Java the 1.5 way. I was reading Effective Java by Joshua Bloch and I came across an interesting piece of information on singletons. If I was asked to write singleton in Java until this point of time, I would probably write this way:. Public class Singleton {. Private static Singleton instance;. Public static synchronized Singleton getInstance() {. Singleton = new Singleton();. Public class Singleton {. Public enum Singleton {.

5

Programming , Algorithms and Random Stuffs: Conversion from infix to postfix

http://codinggeeks.blogspot.com/2010/06/conversion-from-infix-to-postfix.html

Programming , Algorithms and Random Stuffs. Monday, June 7, 2010. Conversion from infix to postfix. Returns true if stk precedes infix. Bool precedes(char stk, char infix) {. Declare an array of operators in precedence order. Considers only 4 operators now. Static char prec[] ={'/','*',' ','-'};. For(int i = 0; i. Std: string postfix(const std: string &infix) {. Std: stack char op stack;. Std: string post fix;. If it is a digit add it to postfix. Post fix.append(1,infix[i]);. The post fix string.

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codinggeeks.blogspot.com

Programming , Algorithms and Random Stuffs

Programming , Algorithms and Random Stuffs. Saturday, May 6, 2017. Given a root of the binary tree and nodes n1 and n2. Find the lowest common ancestor of the nodes. The lowest common ancestor for D and E in the above tree is C. The least common ancestor for D and B is A. Lowest common ancestor with parent pointer. Here is the code:. Node *lca parent(Node *n1, Node *n2) { Node *t1 = n1, *t2 = n2; int c1 = 0, c2 =0; / Find the distance to the root for n1 while(t1! N2) { res = false; } return res l r; }.

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