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coding hangover | eat pray code :)

eat pray code :)

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coding hangover | eat pray code :) | codinghangover.wordpress.com Reviews
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eat pray code :)
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coding hangover | eat pray code :) | codinghangover.wordpress.com Reviews

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eat pray code :)

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1

Spoj (QUE1) Queue (Rookie) | coding hangover

https://codinghangover.wordpress.com/2015/03/25/spoj-que1-queue-rookie

Eat pray code :). Spoj (QUE1) Queue (Rookie). March 25, 2015. Problem link – http:/ www.spoj.com/problems/QUE1/. Vector of pairs is used to store the height and count of taller person standing before. This problem can be solved by sorting the vector based on height. Assign the final position for each person i in the answer array by moving them C empty positions from the index 0 where. C = count of taller person who are standing before person i. Detailed explanation is in the comments of the code below.

2

Codeforces #224 (Div. 2) C. Arithmetic Progression | coding hangover

https://codinghangover.wordpress.com/2015/03/21/codeforces-224-div-2-c-arithmetic-progression

Eat pray code :). Codeforces #224 (Div. 2) C. Arithmetic Progression. March 21, 2015. Problem link – http:/ codeforces.com/problemset/problem/382/C. Codeforces Beta Round #84 (Div. 1) A. Lucky Sum of Digits. Solving K-Palindrome problem using Edit distance algorithm →. Leave a Reply Cancel reply. Enter your comment here. Fill in your details below or click an icon to log in:. Address never made public). You are commenting using your WordPress.com account. ( Log Out. Notify me of new comments via email.

3

Spoj( ONEZERO ) – Ones and zeros | coding hangover

https://codinghangover.wordpress.com/2015/05/01/spoj-onezero-ones-and-zeros

Eat pray code :). Spoj( ONEZERO ) – Ones and zeros. May 1, 2015. Problem link: http:/ www.spoj.com/problems/ONEZERO/. Suppose the number that you want is X. X mod N = 0. So you need to store only N states i.e. 0 to n-1. Start with 1. Implement bfs approach. If the current state modulo is Y, append 0 to it i.e calculate Y*10 0 and find its modulo which will lead you to a new modulo state. Similary append 1 to Y. i.e calculate Y*10 1 and find its modulo. Consisting only of digits 1 and 0 beginning with 1).

4

Solving K-Palindrome problem using Edit distance algorithm | coding hangover

https://codinghangover.wordpress.com/2015/03/22/solving-k-palindrome-problem-using-edit-distance-algorithm

Eat pray code :). Solving K-Palindrome problem using Edit distance algorithm. March 22, 2015. A k-palindrome is a string which transforms into a palindrome on removing at most k characters. Given a string S, and an interger K, print “YES” if S is a k-palindrome; otherwise print “NO”. S has at most 20,000 characters. Input – abxa 1. Output – YES. Input – abdxa 1. Output – No. A string S is K-palindrome if editDistance(S,reverse(S) =2*K. This will be more clear with an example. Let S=madtam and K=1. Now th...

5

vishnujayvel | coding hangover

https://codinghangover.wordpress.com/author/vishnujayvel

Eat pray code :). Spoj( ONEZERO ) – Ones and zeros. May 1, 2015. Problem link: http:/ www.spoj.com/problems/ONEZERO/. Suppose the number that you want is X. X mod N = 0. So you need to store only N states i.e. 0 to n-1. Start with 1. Implement bfs approach. If the current state modulo is Y, append 0 to it i.e calculate Y*10 0 and find its modulo which will lead you to a new modulo state. Similary append 1 to Y. i.e calculate Y*10 1 and find its modulo. Consisting only of digits 1 and 0 beginning with 1).

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coding hangover | eat pray code :)

Eat pray code :). Spoj( ONEZERO ) – Ones and zeros. May 1, 2015. Problem link: http:/ www.spoj.com/problems/ONEZERO/. Suppose the number that you want is X. X mod N = 0. So you need to store only N states i.e. 0 to n-1. Start with 1. Implement bfs approach. If the current state modulo is Y, append 0 to it i.e calculate Y*10 0 and find its modulo which will lead you to a new modulo state. Similary append 1 to Y. i.e calculate Y*10 1 and find its modulo. Consisting only of digits 1 and 0 beginning with 1).

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