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My .NET encounters

Tuesday, December 8, 2009. The below code snippet shows how .NET evaluates expressions in if statement. String x = null;. String.IsNullOrEmpty(x) & x.ToString().Equals(" ). If (string.IsNullOrEmpty(x) x.ToString().Equals(" ). Thursday, December 3, 2009. Parsing comma separated string. Following is the simple code to parse comma separated string into a string array. This StringSplitOptions reduces the overhead on developers. It trims ',' charaters (ie if any , present in the begining or end). Service cann...

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My .NET encounters | dotnetdinesh.blogspot.com Reviews

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Tuesday, December 8, 2009. The below code snippet shows how .NET evaluates expressions in if statement. String x = null;. String.IsNullOrEmpty(x) & x.ToString().Equals( ). If (string.IsNullOrEmpty(x) x.ToString().Equals( ). Thursday, December 3, 2009. Parsing comma separated string. Following is the simple code to parse comma separated string into a string array. This StringSplitOptions reduces the overhead on developers. It trims ',' charaters (ie if any , present in the begining or end). Service cann...

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My .NET encounters | dotnetdinesh.blogspot.com Reviews

https://dotnetdinesh.blogspot.com

Tuesday, December 8, 2009. The below code snippet shows how .NET evaluates expressions in if statement. String x = null;. String.IsNullOrEmpty(x) & x.ToString().Equals(" ). If (string.IsNullOrEmpty(x) x.ToString().Equals(" ). Thursday, December 3, 2009. Parsing comma separated string. Following is the simple code to parse comma separated string into a string array. This StringSplitOptions reduces the overhead on developers. It trims ',' charaters (ie if any , present in the begining or end). Service cann...

INTERNAL PAGES

dotnetdinesh.blogspot.com

1

My .NET encounters: WCF service hosting within Windows service - Issue

http://dotnetdinesh.blogspot.com/2009/12/wcf-hosting-within-windows-service.html

Wednesday, December 2, 2009. WCF service hosting within Windows service - Issue. I faced the exception mentioned below when hosting a WCF service in a windows service. When i tried to start the windows serivce i got an message box throwing the following information:. The Service1 service on Local Computer started and then stopped. Some services stop automatically if they have no work to do, for example, the Performance Logs and Alerts service. Solution for the below exception:. 3 Click on properties.

2

My .NET encounters: Parsing comma separated string

http://dotnetdinesh.blogspot.com/2009/12/parsing-comma-separated-string.html

Thursday, December 3, 2009. Parsing comma separated string. Following is the simple code to parse comma separated string into a string array. This StringSplitOptions reduces the overhead on developers. It trims ',' charaters (ie if any , present in the begining or end). It removes any empty values (ie "Dinesh, Uthayakumar"). String Name = "Dinesh,Uthayakumar,Din";. String[] fullname = Name.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries);. Console.Write(fullname.Length);.

3

My .NET encounters: Short Circuit Evaluation

http://dotnetdinesh.blogspot.com/2009/12/short-circuit-evaluation.html

Tuesday, December 8, 2009. The below code snippet shows how .NET evaluates expressions in if statement. String x = null;. String.IsNullOrEmpty(x) & x.ToString().Equals(" ). If (string.IsNullOrEmpty(x) x.ToString().Equals(" ). Subscribe to: Post Comments (Atom). Parsing comma separated string. WCF service hosting within Windows service - Issue. Http:/ techydinesh.wordpress.com. View my complete profile.

4

My .NET encounters: October 2009

http://dotnetdinesh.blogspot.com/2009_10_01_archive.html

Sunday, October 25, 2009. Here is a method where we could validate a string as a GUID using Regex pattern matching. It validates the guid case insensitively. String.IsNullOrEmpty(Id) & Regex.IsMatch(Id, " [A-Za-z0-9]{8}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{12}$");. Subscribe to: Posts (Atom). Http:/ techydinesh.wordpress.com. View my complete profile.

5

My .NET encounters: Guid Validation

http://dotnetdinesh.blogspot.com/2009/10/guid-validation.html

Sunday, October 25, 2009. Here is a method where we could validate a string as a GUID using Regex pattern matching. It validates the guid case insensitively. String.IsNullOrEmpty(Id) & Regex.IsMatch(Id, " [A-Za-z0-9]{8}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{4}-[A-Za-z0-9]{12}$");. Subscribe to: Post Comments (Atom). Http:/ techydinesh.wordpress.com. View my complete profile.

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My .NET encounters

Tuesday, December 8, 2009. The below code snippet shows how .NET evaluates expressions in if statement. String x = null;. String.IsNullOrEmpty(x) & x.ToString().Equals(" ). If (string.IsNullOrEmpty(x) x.ToString().Equals(" ). Thursday, December 3, 2009. Parsing comma separated string. Following is the simple code to parse comma separated string into a string array. This StringSplitOptions reduces the overhead on developers. It trims ',' charaters (ie if any , present in the begining or end). Service cann...

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