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The eloquence of... Maths: Free maths help, advice and ramblingsFree maths help, advice and general mathematical ramblings
http://eloquentmath.blogspot.com/
Free maths help, advice and general mathematical ramblings
http://eloquentmath.blogspot.com/
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The eloquence of... Maths: Free maths help, advice and ramblings | eloquentmath.blogspot.com Reviews
https://eloquentmath.blogspot.com
Free maths help, advice and general mathematical ramblings
The eloquence of... Maths: Free maths help, advice and ramblings
http://eloquentmath.blogspot.com/2011_10_01_archive.html
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Monday, 31 October 2011. Different Sizes of Infinity. Before you read this make sure you have a basic knowledge of sets. Now if we pair the natural numbers, N {1, 2, 3, .}, and the integers, Z {-2, -1, 0, 1, 2, .}, we will be able to see which set is larger. We pair the numbers up like so:. When we continue to pair up the numbers we discover that the rationa...
The eloquence of... Maths: Free maths help, advice and ramblings
http://eloquentmath.blogspot.com/2012_07_01_archive.html
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Sunday, 15 July 2012. Understanding the Higgs Boson. Unless you have been hiding under a rock somewhere you will almost certainly have seen the news that the Higgs boson has been 'discovered', I say this tentatively as it has not officially been confirmed just a 'Higgs-like' particle has been observed. But what even is the Higgs boson? But is this it? Thankf...
The eloquence of... Maths: Free maths help, advice and ramblings
http://eloquentmath.blogspot.com/2011_12_01_archive.html
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Thursday, 15 December 2011. I recently encountered a mathematical problem from NRich Maths. About inscribed circles in an equilateral triangle and it really intrigued and after a little bit of intense thought I managed to figure it out. For those of who wish to know what the problem is without clicking the link:. Is continued ad infinitum. The height of the ...
The eloquence of... Maths: Free maths help, advice and ramblings
http://eloquentmath.blogspot.com/2011_11_01_archive.html
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Wednesday, 30 November 2011. AS Maths Core 1: Polynomials. The discriminant of a quadratic equation is something that can tell you how many real roots a quadratic equation will have. If we look at the quadratic equation. Then the quadratic has two distinct real roots. Then the quadratic has one repeated real root. Then the quadratic has no real roots. Now, q...
The eloquence of... Maths: Free maths help, advice and ramblings
http://eloquentmath.blogspot.com/2012_12_01_archive.html
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Wednesday, 19 December 2012. Fibonacci Numbers and Continued Fractions. I feel I needed an updated post on the Fibonacci sequence with some of the more core ideas behind it, you can still access the old post. The definition of the Fibonacci sequence is:. Begin{align}F {n 2}=F {n 1}=F n where F 0=1, F 1=1 end{align}$. Only one of these two possible x values a...
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The eloquence of... Maths: Free maths help, advice and ramblings
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Thursday, 21 February 2013. Proving the Chain Rule. We know from basic differentiation. That $ begin{align*} frac{d}{dx}(g(x) = lim {h to 0} left( frac{g(x h) - g(x)}{h} right) end{align*}$. Let $ begin{align*}v = frac{g(x h) - g(x)}{h} - g'(x) (1) end{align*}$ clearly $v to 0 as h to 0$. Rearranging $(1)$ and $(2)$ we get:. The left hand side of this statem...
The eloquence of... Maths: Free maths help, advice and ramblings
I will be showing you all the beauty, and the sheer amazing spectrum that maths can offer you. Please like us on Facebook. And follow us on Twitter. Thursday, 21 February 2013. Proving the Chain Rule. We know from basic differentiation. That $ begin{align*} frac{d}{dx}(g(x) = lim {h to 0} left( frac{g(x h) - g(x)}{h} right) end{align*}$. Let $ begin{align*}v = frac{g(x h) - g(x)}{h} - g'(x) (1) end{align*}$ clearly $v to 0 as h to 0$. Rearranging $(1)$ and $(2)$ we get:. The left hand side of this statem...
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