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Fun with numbers

Wednesday, 27 January 2016. This is with reference to my earlier blog where the dimensions of a box are x y and z and these satisfy 3 equations and I wanted you to find the volume of the box. Multiplying both the right and left hand sides of the 3 equations we get. Xyz x y z 1/x 1/y 1/z 1/xyz=4*7/3*1=28/3. But adding both sides of the equations we get x 1/x y 1/y z 1/z=4 7/3 1=22/3. Deducting result 2 from result1 we get xyz 1/xyz=2. Sunday, 27 December 2015. X (1/y)=4.y (1/z)=1.z (1/x)=7/3. Syrup 7/12-1...

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Fun with numbers | h-rajan.blogspot.com Reviews

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Wednesday, 27 January 2016. This is with reference to my earlier blog where the dimensions of a box are x y and z and these satisfy 3 equations and I wanted you to find the volume of the box. Multiplying both the right and left hand sides of the 3 equations we get. Xyz x y z 1/x 1/y 1/z 1/xyz=4*7/3*1=28/3. But adding both sides of the equations we get x 1/x y 1/y z 1/z=4 7/3 1=22/3. Deducting result 2 from result1 we get xyz 1/xyz=2. Sunday, 27 December 2015. X (1/y)=4.y (1/z)=1.z (1/x)=7/3. Syrup 7/12-1...

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Fun with numbers | h-rajan.blogspot.com Reviews

https://h-rajan.blogspot.com

Wednesday, 27 January 2016. This is with reference to my earlier blog where the dimensions of a box are x y and z and these satisfy 3 equations and I wanted you to find the volume of the box. Multiplying both the right and left hand sides of the 3 equations we get. Xyz x y z 1/x 1/y 1/z 1/xyz=4*7/3*1=28/3. But adding both sides of the equations we get x 1/x y 1/y z 1/z=4 7/3 1=22/3. Deducting result 2 from result1 we get xyz 1/xyz=2. Sunday, 27 December 2015. X (1/y)=4.y (1/z)=1.z (1/x)=7/3. Syrup 7/12-1...

INTERNAL PAGES

h-rajan.blogspot.com

1

Fun with numbers: June 2015

http://h-rajan.blogspot.com/2015_06_01_archive.html

Thursday, 11 June 2015. A sequence of numbers a1,a2,a3,. a100 has the property that for every integer k between 1 and k inclusive,the number ak is k less than the sum of the other 99 numbers.Find the 50th number of the sequence. Subscribe to: Posts (Atom). View my complete profile. Simple template. Powered by Blogger.

2

Fun with numbers: December 2013

http://h-rajan.blogspot.com/2013_12_01_archive.html

Thursday, 19 December 2013. Collecting numbers for particular sums-2. This is a rejoinder to my earlier blog with same title. There has been no response although it is a simple problem of logic. For exnmple instead of collecting 6 numbers from group A,you can consider removing 2 numbers from that group. Same logic with group B. Following are the solutions. Group A-total 220- by removing 55 and 11.group B-total 110- by removing 38 and 49. Is it not simple? Thursday, 5 December 2013.

3

Fun with numbers: Page numbers of a book-Rejoinder

http://h-rajan.blogspot.com/2015/03/page-numbers-of-book-rejoinder.html

Saturday, 21 March 2015. Page numbers of a book-Rejoinder. There has been no response so far. However the solution can be arrived at as follows-. If there were 63 pages in the book,the sum of the page numbers from 1 to 63 will be 2016. As the addition of an extra page number gave the total 2014,the total number of pages could not be 63 but 62. For 62 pages the sum of the page numbers will be 1953 and so the page number added wrongly should be 2014-1953=61. Subscribe to: Post Comments (Atom).

4

Fun with numbers: December 2014

http://h-rajan.blogspot.com/2014_12_01_archive.html

Tuesday, 23 December 2014. Page numbers of a book. A puzzle from Monday Edex issue (New Indian Express) of 9 june 2014-. The pages of a book are numbered 1 to n.When the page numbers were added by someone just for fun,one of the page numbers were added twice,resulting in an incorrect sum of 2014.Find the page number which was wrongly added twice. Subscribe to: Posts (Atom). Page numbers of a book. View my complete profile. Simple template. Powered by Blogger.

5

Fun with numbers: September 2014

http://h-rajan.blogspot.com/2014_09_01_archive.html

Tuesday, 16 September 2014. A number sequence to be filled-Rejoinder. I had asked readers to find the next number in the sequence 10,9,60,90,70,66. I had also suggested to treat this as an alpha-numeric sequence . The numbers given are the number of alphabets which are required for expressing the highest numbers with 3,4,5,6,7,and 8 alphabets. You are thus required to find the highest number which needs 9 alphabets for expression. No one has given a solution. Let us first consider numbers from 90 to 99.

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h-rajan.blogspot.com

Fun with numbers

Wednesday, 27 January 2016. This is with reference to my earlier blog where the dimensions of a box are x y and z and these satisfy 3 equations and I wanted you to find the volume of the box. Multiplying both the right and left hand sides of the 3 equations we get. Xyz x y z 1/x 1/y 1/z 1/xyz=4*7/3*1=28/3. But adding both sides of the equations we get x 1/x y 1/y z 1/z=4 7/3 1=22/3. Deducting result 2 from result1 we get xyz 1/xyz=2. Sunday, 27 December 2015. X (1/y)=4.y (1/z)=1.z (1/x)=7/3. Syrup 7/12-1...

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