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_(:3JZ)_ | Make A Difference

密码保护 part of my diary. 2013 ACM-ICPC Chengdu Invitational. 2013 ACM-ICPC Hangzhou Invitational. I [1,k],i Z. Nequals(BigInteger.ZERO) { ans=ans.add(n.add(BigInteger.ONE).shiftRight(1) ; n=n.shiftRight(k); }. 2013 ACM-ICPC Changsha Invitational. 观察一下x和y,可以得到一个递推关系 翻草稿纸) 诶 不见了 啊在这里. 2013 ACM-ICPC Nanjing Invitational. 2013 ACM-ICPC Tonghua Invitational. First blood is mine. 2012 Asia Chengdu Regional Contest. Inline ll cal(ll n) { if(n&1) n =3; n =1; n*=n; static int k; k=n%12; n/=12; return n (k =6); }.

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_(:3JZ)_ | Make A Difference | himemeizhi.com Reviews
<META>
DESCRIPTION
密码保护 part of my diary. 2013 ACM-ICPC Chengdu Invitational. 2013 ACM-ICPC Hangzhou Invitational. I [1,k],i Z. Nequals(BigInteger.ZERO) { ans=ans.add(n.add(BigInteger.ONE).shiftRight(1) ; n=n.shiftRight(k); }. 2013 ACM-ICPC Changsha Invitational. 观察一下x和y,可以得到一个递推关系 翻草稿纸) 诶 不见了 啊在这里. 2013 ACM-ICPC Nanjing Invitational. 2013 ACM-ICPC Tonghua Invitational. First blood is mine. 2012 Asia Chengdu Regional Contest. Inline ll cal(ll n) { if(n&1) n =3; n =1; n*=n; static int k; k=n%12; n/=12; return n (k =6); }.
<META>
KEYWORDS
1 make a difference
2 跳至内容
3 code library
4 要查看留言请输入您的密码
5 这是一篇受密码保护的文章,您需要提供访问密码
6 本条目发布于
7 属于 uncategorized
8 分类,被贴了 diary
9 作者是 himemeizhi
10 发表回复
CONTENT
Page content here
KEYWORDS ON
PAGE
make a difference,跳至内容,code library,要查看留言请输入您的密码,这是一篇受密码保护的文章,您需要提供访问密码,本条目发布于,属于 uncategorized,分类,被贴了 diary,作者是 himemeizhi,发表回复,やるだけ,三分 ry,虽然可以dp倍增,但是 lct,写起来实在不用动脑筋 ry,与其说是dp不如说是披着dp外衣的数据结构水题吧 ry,用线段树然后在最底层套一排multiset大概没有比窝更懒的写法了 ry,最小覆盖圆 ry,继续阅读 →,java
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_(:3JZ)_ | Make A Difference | himemeizhi.com Reviews

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密码保护 part of my diary. 2013 ACM-ICPC Chengdu Invitational. 2013 ACM-ICPC Hangzhou Invitational. I [1,k],i Z. Nequals(BigInteger.ZERO) { ans=ans.add(n.add(BigInteger.ONE).shiftRight(1) ; n=n.shiftRight(k); }. 2013 ACM-ICPC Changsha Invitational. 观察一下x和y,可以得到一个递推关系 翻草稿纸) 诶 不见了 啊在这里. 2013 ACM-ICPC Nanjing Invitational. 2013 ACM-ICPC Tonghua Invitational. First blood is mine. 2012 Asia Chengdu Regional Contest. Inline ll cal(ll n) { if(n&1) n =3; n =1; n*=n; static int k; k=n%12; n/=12; return n (k =6); }.

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_(:3JZ)_ | Make A Difference

密码保护 part of my diary. 2013 ACM-ICPC Chengdu Invitational. 2013 ACM-ICPC Hangzhou Invitational. I [1,k],i Z. Nequals(BigInteger.ZERO) { ans=ans.add(n.add(BigInteger.ONE).shiftRight(1) ; n=n.shiftRight(k); }. 2013 ACM-ICPC Changsha Invitational. 观察一下x和y,可以得到一个递推关系 翻草稿纸) 诶 不见了 啊在这里. 2013 ACM-ICPC Nanjing Invitational. 2013 ACM-ICPC Tonghua Invitational. First blood is mine. 2012 Asia Chengdu Regional Contest. Inline ll cal(ll n) { if(n&1) n =3; n =1; n*=n; static int k; k=n%12; n/=12; return n (k =6); }.

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