icodeyou.com
把编程当做一种爱icodeyou的博客
http://www.icodeyou.com/
icodeyou的博客
http://www.icodeyou.com/
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3/F.,HiChina Mansion,No.27 ●●●●●●●●●●●●●●●●●●●●●●●●●●●strict,Beijing 100120,China
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CN
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DOMAIN WHOIS PROTECTION SERVICE
WHOIS AGENT
3/F.,HiChina Mansion,No.27 ●●●●●●●●●●●●●●●●●●●●●●●●●●●strict,Beijing 100120,China
Be●●ng , Beijing, 100120
CN
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DOMAIN WHOIS PROTECTION SERVICE
WHOIS AGENT
3/F.,HiChina Mansion,No.27 ●●●●●●●●●●●●●●●●●●●●●●●●●●●strict,Beijing 100120,China
Be●●ng , Beijing, 100120
CN
View this contact
DOMAIN WHOIS PROTECTION SERVICE
WHOIS AGENT
3/F.,HiChina Mansion,No.27 ●●●●●●●●●●●●●●●●●●●●●●●●●●●strict,Beijing 100120,China
Be●●ng , Beijing, 100120
CN
View this contact
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把编程当做一种爱 | icodeyou.com Reviews
https://icodeyou.com
icodeyou的博客
icodeyou.com
Works | 把编程当做一种爱
http://icodeyou.com/works
创意表白应用 捅破窗户纸 前24h PV 10W UIP 3W. 微信头像 Anyone 应用 前24h PV 40W UIP 8W.
科技之星 | 把编程当做一种爱
http://icodeyou.com/citstar
视频教程 | 把编程当做一种爱
http://icodeyou.com/videos
Android 中 Action Bar 的使用. Android 侧滑菜单之 DrawerLayout 的使用.
TOTAL PAGES IN THIS WEBSITE
3
浅析CVE-2012-0158 - lynahex' blog
http://www.lynahex.com/index.php/archives/CVE-2012-0158.html
本文由 lynahex 发表于 2016 年 08 月 01 日. 该漏洞是一个典型的栈溢出漏洞，在MSCOMCTL.ocx ActiveX控件中解析.DOC、.RTF、XLS等格式时，其数据流的反序列化过程中，MSCOMCTL读取大小字段流时，将它复制到一个固定大小的堆栈缓冲区。 IDA Pro 6.8. 运行shellcode，通过监控发现了在C: Documents and Settings Administrator生成临时文件a.exe。 Py mona find -type bin -b 100000 -t 130000 -s 90909090，可能之后的操作覆盖刷新了栈. 重新运行程序，对jmp esp处下执行断点ba e1 0x7ffa4512。 重新运行程序，在0x11aa84处下写断点 ba w1 0x11aa84. 同时在0x7ffa4512处下执行断点 ba e1 0x7ffa4512. Sxn -c "r eip; dd 0x11abfc 1" sse. 先对MSCOMCTL.OCX下断， sxe ld:MSCOMCTL.OCX. Pwnhub 打开电脑 之 误 wp.
lynahex' blog
http://www.lynahex.com/index.php/page/2
Teaser CONFidence CTF 2015 Practical Numerology. Pwnhub 打开电脑 之 误 wp. 2016 hitcon ctf web writeup. 1 搜索CVE-2016-0701 进入 https:/ cv.
PAT 1052 Linked List Sorting (25) | CodeLife
https://www.zacharyjia.me/2016/03/01/PAT-1052
PAT 1052 Linked List Sorting (25). A linked list consists of a series of structures, which are not necessarily adjacent in memory. We assume that each structure contains an integer key and a Next pointer to the next structure. Now given a linked list, you are supposed to sort the structures according to their key values in increasing order. Then N lines follow, each describes a node in the format:. Addr, key, next;. Node &a, const. Akey b.key;. N, &start);. Addr, key, next;. Addr, &key, &next);.
PAT 1051 Pop Sequence (25) | CodeLife
https://www.zacharyjia.me/2016/02/29/PAT-1051
PAT 1051 Pop Sequence (25). Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): M (the maximum capacity of the stack), N (the length of push sequence), and K (the number of pop sequences to be checked). Then K lines follow, each contains a pop sequence of N numbers. All the numbers in a line are separated by a space. For each pop sequence, print in one line YES if it is indeed a possible pop sequence of the stack, or NO if not. Num cur & num!
Tag: PAT | CodeLife
https://www.zacharyjia.me/tags/PAT
PAT 1052 Linked List Sorting (25). PAT 1051 Pop Sequence (25). PAT 1048 Find Coins (25). PAT-1047 Student List for Course (25). PAT 1033 To Fill or Not to Fill (25). PAT 1039 Course List for Student(25). 2015 - 2017 Zachary Jia.
PAT 1048 Find Coins (25) | CodeLife
https://www.zacharyjia.me/2016/02/29/PAT-1048
PAT 1048 Find Coins (25). Each input file contains one test case. For each case, the first line contains 2 positive numbers: N ( =105, the total number of coins) and M( =103, the amount of money Eva has to pay). The second line contains N face values of the coins, which are all positive numbers no more than 500. All the numbers in a line are separated by a space. Sort(coins, coins n);. Start, end, mid;. Start = i 1. End = n - 1. Mid = (start end) / 2. M & end = start & start = i 1. End = n - 1.
Archives | CodeLife
https://www.zacharyjia.me/archives
PAT 1052 Linked List Sorting (25). PAT 1051 Pop Sequence (25). PAT 1048 Find Coins (25). PAT-1047 Student List for Course (25). PAT 1033 To Fill or Not to Fill (25). 2015 - 2017 Zachary Jia.
Tag: 算法 | CodeLife
https://www.zacharyjia.me/tags/算法
PAT 1052 Linked List Sorting (25). PAT 1051 Pop Sequence (25). PAT 1048 Find Coins (25). PAT-1047 Student List for Course (25). PAT 1033 To Fill or Not to Fill (25). PAT 1039 Course List for Student(25). 2015 - 2017 Zachary Jia.
TOTAL LINKS TO THIS WEBSITE
39
icodex.ru
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Icodextrin
Find the best information and most relevant links on all topics related to icodextrin.com.
Icodey - Custom Development from Apps to Websites
For Apps, Websites, SaaS,. Database, API's and Everything In-Between. We have been building custom web applications. For over 10 years. Our knowledge and experience spans many different languages including. PHP, ASP.net, C#, Python, and Java. Our new website is. We are busy working on projects for our clients and are doing our best to bring the new website online.
icodeya
How to perforn basic authentication in AngularJS? For this tutorial, I'll teach you how to perform a basic authentication with AngularJS. For the sake of example, we'll use github's API for basic authentication. If you browse that page now, you'll see a section for basic auth. See that line with the curl command? Curl -u (username):(token) https:/ api.github.com/user. How to Deploy your Meteor app to a Custom Subdomain. Meteor deploy myapp.example.com. Now open your domain registrar of choice, in this ex...
把编程当做一种爱
我是一个 Android 程序员，使用 Mac 一年了，从各种地方搜集来了很多好用的软件，特此在此记录一下，既方便自己积累用，也供他人参考，本篇长期不定期更新。 Mac 上 ssh-add 永久将私钥添加到 Keychain. 两种连接 Git 服务器的方式，分别为 HTTPS 和 SSH，显然更推荐后者，所以我们经常使用命令. Ssh-keygen -t rsa -C me@icodeyou.com. 即可一劳永逸将私钥添加进 Mac 本身的钥匙串中，即 Keychain。 之前一直在用别人的开源库，尤其有了 Gradle 后，依赖别人的开源库就更简单了，只需要在项目的 build.gradle 文件中添加上类似. Compile com.github.icodeu:CommonAdapter:v1.0. 的就好了，剩下的就可以交给 Gradle 帮助我们完成 library 依赖了。 关于 SerialVersionUID 的概念和作用就不多说了，自行搜索即可，本篇简单说一下如何在 Android Studio 中自动帮助我们生成(不重复的) SerialVersionUID。
I code you play
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icodfrance.com
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