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Searching an Element in a Rotated Sorted Array. April 19, 2014. Check out this code for finding the next palindrome, seems pretty simple to me. Gold Mine: Maximum amount of gold he can collect and path followed by him. April 17, 2014. Initially my first thought was why do we need a DP here, there is no need of memoization. We just have to evaluate all possible paths. It more kind of backtracking in nature. We have to go through all possible cases of start from the first column. Ie O( 3 m)*n). July 6, 2013.

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Searching an Element in a Rotated Sorted Array. April 19, 2014. Check out this code for finding the next palindrome, seems pretty simple to me. Gold Mine: Maximum amount of gold he can collect and path followed by him. April 17, 2014. Initially my first thought was why do we need a DP here, there is no need of memoization. We just have to evaluate all possible paths. It more kind of backtracking in nature. We have to go through all possible cases of start from the first column. Ie O( 3 m)*n). July 6, 2013.

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6 longest increasing subsequence

7 problem statement

8 finding subproblems

9 recurrence relation

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love to code | innosamcodes.wordpress.com Reviews

https://innosamcodes.wordpress.com

Searching an Element in a Rotated Sorted Array. April 19, 2014. Check out this code for finding the next palindrome, seems pretty simple to me. Gold Mine: Maximum amount of gold he can collect and path followed by him. April 17, 2014. Initially my first thought was why do we need a DP here, there is no need of memoization. We just have to evaluate all possible paths. It more kind of backtracking in nature. We have to go through all possible cases of start from the first column. Ie O( 3 m)*n). July 6, 2013.

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innosamcodes.wordpress.com

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innosam « love to code

https://innosamcodes.wordpress.com/author/innosam

Searching an Element in a Rotated Sorted Array. April 19, 2014. Check out this code for finding the next palindrome, seems pretty simple to me. Gold Mine: Maximum amount of gold he can collect and path followed by him. April 17, 2014. Initially my first thought was why do we need a DP here, there is no need of memoization. We just have to evaluate all possible paths. It more kind of backtracking in nature. We have to go through all possible cases of start from the first column. Ie O( 3 m)*n). July 6, 2013.

2

Gold Mine: Maximum amount of gold he can collect and path followed by him. « love to code

https://innosamcodes.wordpress.com/2014/04/17/gold-mine-maximum-amount-of-gold-he-can-collect-and-path-followed-by-him

Searching an Element in a Rotated Sorted Array. Gold Mine: Maximum amount of gold he can collect and path followed by him. April 17, 2014. Given a gold mine of n*m dimension. Each field in this mine contains an integer which is amount of gold in tons. Initially miner is in first column but could be at any row i. He can move only (right - , right up /, right down ). Find out maximum amount of gold he can collect and path followed by him. Ie O( 3 m)*n). And, memoization does help! This entry was tagged DP.

3

June « 2013 « love to code

https://innosamcodes.wordpress.com/2013/06

Searching an Element in a Rotated Sorted Array. Monthly Archives: June 2013. Least Common Ancestor(LCA) of a Binary Tree. June 27, 2013. Bool findCA(node* elem, node* n1, node* n2, node* and result) { if(elem = NULL) return false; bool left = findCA(elem- left, n1, n2, result); bool right = findCA(elem- right, n1, n2, result); bool curr = (n1= elem n2 = elem); if(left & right &! Is the tree a BST! June 16, 2013. Sample Call to the function would be:. IsBST(root, false, 0, false, 0). June 16, 2013. Void b...

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Next Smallest Palindrome « love to code

https://innosamcodes.wordpress.com/2014/04/19/next-smallest-palindrome

Searching an Element in a Rotated Sorted Array. April 19, 2014. Check out this code for finding the next palindrome, seems pretty simple to me. Gold Mine: Maximum amount of gold he can collect and path followed by him. Leave a Reply Cancel reply. Enter your comment here. Fill in your details below or click an icon to log in:. Address never made public). You are commenting using your WordPress.com account. ( Log Out. You are commenting using your Twitter account. ( Log Out.

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Is the tree a BST!! « love to code

https://innosamcodes.wordpress.com/2013/06/16/is-the-tree-a-bst

Searching an Element in a Rotated Sorted Array. Is the tree a BST! June 16, 2013. Bool isBST(treenode* elem, bool isMin, int min, bool isMax, int max){ if(elem= NULL) return true; if(isMin) if(elem- value min ) return false; if(isMax) if(elem- value max) return false; return isBST(elem- left, isMin, min, true, elem- value) & isBST(elem- right, true, elem- value, isMax, max); }. Sample Call to the function would be:. IsBST(root, false, 0, false, 0). Printing a tree in vertical order from LEFT to RIGHT.

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love to code

Searching an Element in a Rotated Sorted Array. April 19, 2014. Check out this code for finding the next palindrome, seems pretty simple to me. Gold Mine: Maximum amount of gold he can collect and path followed by him. April 17, 2014. Initially my first thought was why do we need a DP here, there is no need of memoization. We just have to evaluate all possible paths. It more kind of backtracking in nature. We have to go through all possible cases of start from the first column. Ie O( 3 m)*n). July 6, 2013.

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