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October 10, 2016. Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array. 2,1,-3,4,-1,2,1,-5,4]. 4,-1,2,1]. Has the largest sum =. If you have figured out the O(. Solution, try coding another solution using the divide and conquer approach, which is more subtle. 用iMax表示包含第i个元素的subArray的最大值，那么iMax(i) = max( iMax. I -1) nums[i] , iMax. 还有一个类似的解法，思路是保证i之前的最大值是个非负数，那么到i的 iMax 就是 iMax nums[i]。 2 O(nLogn)的divide and conquer 解法.

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J to ST | Jackey to ST | j2st.com Reviews

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October 10, 2016. Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array. 2,1,-3,4,-1,2,1,-5,4]. 4,-1,2,1]. Has the largest sum =. If you have figured out the O(. Solution, try coding another solution using the divide and conquer approach, which is more subtle. 用iMax表示包含第i个元素的subArray的最大值，那么iMax(i) = max( iMax. I -1) nums[i] , iMax. 还有一个类似的解法，思路是保证i之前的最大值是个非负数，那么到i的 iMax 就是 iMax nums[i]。 2 O(nLogn)的divide and conquer 解法.

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October 10, 2016. Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array. 2,1,-3,4,-1,2,1,-5,4]. 4,-1,2,1]. Has the largest sum =. If you have figured out the O(. Solution, try coding another solution using the divide and conquer approach, which is more subtle. 用iMax表示包含第i个元素的subArray的最大值，那么iMax(i) = max( iMax. I -1) nums[i] , iMax. 还有一个类似的解法，思路是保证i之前的最大值是个非负数，那么到i的 iMax 就是 iMax nums[i]。 2 O(nLogn)的divide and conquer 解法.

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October 10, 2016. Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array. 2,1,-3,4,-1,2,1,-5,4]. 4,-1,2,1]. Has the largest sum =. If you have figured out the O(. Solution, try coding another solution using the divide and conquer approach, which is more subtle. 用iMax表示包含第i个元素的subArray的最大值，那么iMax(i) = max( iMax. I -1) nums[i] , iMax. 还有一个类似的解法，思路是保证i之前的最大值是个非负数，那么到i的 iMax 就是 iMax nums[i]。 2 O(nLogn)的divide and conquer 解法.

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