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Your site for all things Jesse Conner. Calculating an exponent in O(log n). In my algorithms class the teacher challenged us to come up with an algorithm that calculates the value of a base raised to an exponent recursively. Obviously this is quite easy to do in O(n) but he pushed us to figure out a way to do it in O(log n). After playing around a bit I think that I have come up with a good algorithm. Unsigned int64 exponent(unsigned int base, unsigned int exp) { if (exp. Jesse Conner - May 15, 2014 - C.

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Your site for all things Jesse Conner. Calculating an exponent in O(log n). In my algorithms class the teacher challenged us to come up with an algorithm that calculates the value of a base raised to an exponent recursively. Obviously this is quite easy to do in O(n) but he pushed us to figure out a way to do it in O(log n). After playing around a bit I think that I have come up with a good algorithm. Unsigned int64 exponent(unsigned int base, unsigned int exp) { if (exp. Jesse Conner - May 15, 2014 - C.

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Your site for all things Jesse Conner. Calculating an exponent in O(log n). In my algorithms class the teacher challenged us to come up with an algorithm that calculates the value of a base raised to an exponent recursively. Obviously this is quite easy to do in O(n) but he pushed us to figure out a way to do it in O(log n). After playing around a bit I think that I have come up with a good algorithm. Unsigned int64 exponent(unsigned int base, unsigned int exp) { if (exp. Jesse Conner - May 15, 2014 - C.

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m_i_rite – Code

http://www.m-i-rite.com/category/code

Your site for all things Jesse Conner. Calculating an exponent in O(log n). In my algorithms class the teacher challenged us to come up with an algorithm that calculates the value of a base raised to an exponent recursively. Obviously this is quite easy to do in O(n) but he pushed us to figure out a way to do it in O(log n). After playing around a bit I think that I have come up with a good algorithm. Unsigned int64 exponent(unsigned int base, unsigned int exp) { if (exp. Jesse Conner - May 15, 2014 - C.

2

m_i_rite – Web

http://www.m-i-rite.com/category/code/web

Your site for all things Jesse Conner. Simple HTML Countdown Page. Today I set out to make a simple HTML countdown. I was pleased with the results, so I have decided to share my source. DOCTYPE html html lang=en xmlns=http:/ www.w3.org/1999/xhtml head meta charset=utf-8 / title Countdown /title link href=style.css rel=stylesheet / script src=countdown.js /script /head body onload=setTime() div id=console /div /body /html. Once again this is pretty straight forward. By positioning it absolute at 0,0,0...

3

m_i_rite – Reversing a stack in C++

http://www.m-i-rite.com/reversing-a-stack-in-c

Your site for all things Jesse Conner. Reversing a stack in C. I think that the simplest way to reverse a stack in C is to use some basic recursion to assign each element the address of its predecessor. The code goes as follows (building on this sample code. Void Stack: reassign(Node* lastAddr, Node* target) { if(target) { reassign(target, target- next); if(! Target- next) top=target; target- next=lastAddr; } } void Stack: reverse() { reassign( Node*)0, top); }. Jesse Conner - October 8, 2013 - C.

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m_i_rite – My Pretty Little Liars Theory

http://www.m-i-rite.com/my-pretty-little-liars-theory

Your site for all things Jesse Conner. My Pretty Little Liars Theory. Additional clues have surfaced over the seasons that Alison is not actually dead. If I recall correctly the person hiding in the Dilaurentis house has still not been explained, and someone obviously saved the liars from the fire at the lodge. Baring any supernatural activity (Which would be a first for the series) I believe that it is a reasonable conclusion that Allie is still alive. So then who died?

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Your site for all things Jesse Conner. Calculating an exponent in O(log n). In my algorithms class the teacher challenged us to come up with an algorithm that calculates the value of a base raised to an exponent recursively. Obviously this is quite easy to do in O(n) but he pushed us to figure out a way to do it in O(log n). After playing around a bit I think that I have come up with a good algorithm. Unsigned int64 exponent(unsigned int base, unsigned int exp) { if (exp. Jesse Conner - May 15, 2014 - C.

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