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mathsmathsmaths.blogspot.com

mathsmathsmaths.com

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all.

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mathsmathsmaths.com | mathsmathsmaths.blogspot.com Reviews

https://mathsmathsmaths.blogspot.com

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all.

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1

mathsmathsmaths.com: Remainder Theorem

http://mathsmathsmaths.blogspot.com/2011/06/remainder-theorem.html

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all. Wednesday, June 15, 2011. 1)2x 2 6x 3 will have the same remainder when divided by x p and x-2q. p does not equal to -2q. So what is p-2q? Remainder Theorem for you is : if f(x) a polynomial is divided by a linear divisor x-a the remainder is f(a). So f(x) 2x 2 6x 3. X p = x-(-p). F(-p) = 2(-p) 2 -6p 3. 2p 2 -6p 3. F(2q) = 2(2q) 2 6.2q 3. 8q 2 12q 3. 2p 2-8q 2 -6p -12q = 0. 2(p 2 -4q ) -6(p 2q) = 0.

2

mathsmathsmaths.com: Problem#4 Interesting Problem

http://mathsmathsmaths.blogspot.com/2011/06/problem4-interesting-problem.html

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all. Friday, June 10, 2011. Here's an interesting problem at Yahoo Answer that I solved this morning. Comments and suggestions and a better approach welcome :). Substitute 0-9 for the alphabets below using all the digits and repeating none. So easily G is 1 . 0 should be in the Answer becuase if 0 2 or something will give result 2. so we will have repeatiton.So lets put H = 0. We are left with 2,3,6,7,8,9.

3

mathsmathsmaths.com: June 2011

http://mathsmathsmaths.blogspot.com/2011_06_01_archive.html

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all. Wednesday, June 15, 2011. 50k cubed-40k squared 75k-60. Anyone know the answer? 50k 3 -40k 2 75k -60. 5(10k 3 -8k 2 15k -12). 5k(2k 3) (5k -4). 1)2x 2 6x 3 will have the same remainder when divided by x p and x-2q. p does not equal to -2q. So what is p-2q? Remainder Theorem for you is : if f(x) a polynomial is divided by a linear divisor x-a the remainder is f(a). So f(x) 2x 2 6x 3. X p = x-(-p).

4

mathsmathsmaths.com: Problem#3 Absolute value problem

http://mathsmathsmaths.blogspot.com/2011/06/problem3-absolute-value-problem.html

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all. Wednesday, June 8, 2011. Problem#3 Absolute value problem. Equation Involving Absolute Value? Solve x 3x-2 = 2. X 3x-2 = 2. X 2 2x 3x-2 9x 2-12x 4= 4. 10x 2-12x 2x 3x-2 =0. X=0 or (5x-6 3x-2 )=0. X=0 or 3x-2 =6-5x. X=0 or 3x-2=6-5x or 2-3x=6-5x. X=0 or x=1 or x=2(rejected). Labels: Absolute value problems. Subscribe to: Post Comments (Atom). There was an error in this gadget. View my complete profile.

5

mathsmathsmaths.com: Problem#1 What is the remainder when you divide 5(raised to 125) by 124?

http://mathsmathsmaths.blogspot.com/2011/06/problem1-what-is-remainder-when-you.html

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all. Wednesday, June 8, 2011. Problem#1 What is the remainder when you divide 5(raised to 125) by 124? Source: Yahoo Answers. The question and my answer here. What is the remainder when you divide 5(raised to 125) by 124? Here, 125 is the power of 5. Please tell the method too. 5 125 = 5 (3.41 2) = 5 3.41 . 5 2. 125 41.5 2. 124 1) 41 . 5 2. 124 41 a 124 43 . 1).25. Subscribe to: Post Comments (Atom).

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mathsmathsmaths.blogspot.com mathsmathsmaths.blogspot.com

mathsmathsmaths.com

A Mathematics enthusiasts guide for students and teachers with the aim of making mathematics easy for all. Wednesday, June 15, 2011. 50k cubed-40k squared 75k-60. Anyone know the answer? 50k 3 -40k 2 75k -60. 5(10k 3 -8k 2 15k -12). 5k(2k 3) (5k -4). 1)2x 2 6x 3 will have the same remainder when divided by x p and x-2q. p does not equal to -2q. So what is p-2q? Remainder Theorem for you is : if f(x) a polynomial is divided by a linear divisor x-a the remainder is f(a). So f(x) 2x 2 6x 3. X p = x-(-p).

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