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matlab comands and graph for -x(y+1) | Agustafson88's Weblog

https://mth212f08agustafson88.wordpress.com/2008/09/12/matlab-comands-and-graph-for-xy1

Just another WordPress.com weblog. Laquo; Previous Post. Matlab comands and graph for -x(y 1). Solution = dsolve(‘Dy=-x*(y 1)’,’y(0)=10′,’x’). X,y]=meshgrid(-5:.5:5,-5:.5:5);. L=sqrt(1 s. 2);. Quiver(x,y,1./l,s./l,.5), axis tight. This entry was posted on September 12, 2008 at 1:54 pm and is filed under Uncategorized. You can follow any responses to this entry through the RSS 2.0. Feed You can leave a response. From your own site. Leave a Reply Cancel reply. Enter your comment here.

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Euler’s method graph | Agustafson88's Weblog

https://mth212f08agustafson88.wordpress.com/2008/09/18/euler’s-method-graph

Just another WordPress.com weblog. Laquo; matlab comands and graph for -x(y 1). This entry was posted on September 18, 2008 at 3:34 pm and is filed under Uncategorized. You can follow any responses to this entry through the RSS 2.0. Feed You can leave a response. From your own site. Leave a Reply Cancel reply. Enter your comment here. Fill in your details below or click an icon to log in:. Address never made public). You are commenting using your WordPress.com account. ( Log Out. Blog at WordPress.com.

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Agustafson88's Weblog

https://mth212f08agustafson88.wordpress.com/2008/09/09/35

Just another WordPress.com weblog. Matlab comands and graph for -x(y 1). I an working on the differential equation. This entry was posted on September 9, 2008 at 3:14 pm and is filed under Uncategorized. You can follow any responses to this entry through the RSS 2.0. Feed You can leave a response. From your own site. Leave a Reply Cancel reply. Enter your comment here. Fill in your details below or click an icon to log in:. Address never made public). Notify me of new comments via email.

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Differential Equation Solution | Agustafson88's Weblog

https://mth212f08agustafson88.wordpress.com/2008/09/19/differential-equation-solution

Just another WordPress.com weblog. Laquo; Euler’s method graph. Second Three Week Project. Was solved three ways. First a direction field was produced, then Euler’s method, finally a solution was found using MATLAB’s dsolve. The quiver command then plots the graph below. This gives a good overall picture of equations flow. Euler’s method is. Which can be solved for. And the results produced the following graph. unfortunately a greater. Wil produre greater error but a smaller. This will return solution =.

5

Fourth Block – Laplace Transforms | Agustafson88's Weblog

https://mth212f08agustafson88.wordpress.com/2008/12/17/fourth-block-laplace-transforms

Just another WordPress.com weblog. Laquo; Third Block. Fourth Block – Laplace Transforms. The differential equations below were solved using Laplace transforms. A benefit of the Laplace (s) domain is that it reduces calculus into algebra. For example integration in the Laplace domain is simply dividing by s and inversely differentiation is multiplying by s. The properties. Prove to be instrumental in solving differential equations. Start by applying the Laplace operation across the equation:. This sectio...

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MTH 212: Weeks 4-6 | Elements of the Domain

https://mirolhado.wordpress.com/mth-212-weeks-4-6

Elements of the Domain. Math as I complied it. MTH 212: Weeks 4-6. Here we have a table of values using Euler’s method. We had an incorrect table for a good while and we realized that we had a problem when we read in one of the cells “feb 2” instead of 8/3. This was our original graph for the functions of x, y, and z versus t. It was a bit small so we eventually increased our domain ‘t’ values and got a much nicer looking graph. 8212;——————————&...8212;———————&#8...Today we modified the rho in our lorenz...

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Agustafson88's Weblog | Just another WordPress.com weblog

Just another WordPress.com weblog. Fourth Block – Laplace Transforms. December 17, 2008. The differential equations below were solved using Laplace transforms. A benefit of the Laplace (s) domain is that it reduces calculus into algebra. For example integration in the Laplace domain is simply dividing by s and inversely differentiation is multiplying by s. The properties. Prove to be instrumental in solving differential equations. Start by applying the Laplace operation across the equation:. This section...

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