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Calculus Homework Help
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Calculus Homework Help Free. Write an equation for the normal to the curve f(x) = $x 2$ - 2 at x = -1. The slope of the tangent to the curve at x = -1 is. Lim {h rightarrow0}$ $ frac{f(h - 1) - f(-1)}{h}$. Lim {h rightarrow0}$ $ frac{(h - 1) 2 - 2 1}{h}$. Lim {h rightarrow0}$ $ frac{h 2 1 - 2h - 1}{h}$. Lim {h rightarrow0}$ $ frac{h 2 - 2h}{h}$. Lim {h rightarrow0}$ (h - 2). Slope of the normal = Negative reciprocal of slope of the tangent. So slope of the normal is $ frac{1}{2}$. Y 1 = $ frac{1}{2}$.
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Free Algebra Homework Help. Solve $ sqrt{x}$ 9 = 13. Sqrt{x}$ 9 = 13. Subtract 9 from both the sides. Sqrt{x}$ 9 - 9 = 13 - 9. To get rid form square root, square each side. Sqrt{x}) 2$ = $4 2$. The value of x is 16. Solve $125 x$ = 625. 125 x$ = 625. 5 {3x}$ = $5 4$ [ $ because$ If $a m = a n$ then m = n ]. Or x = $ frac{4}{3}$. Factor the polynomial $x 2 7x - 30$. X 2 7x - 30$ = $x 2 10x - 3x - 30$ (Split the middle term). X(x 10) - 3(x 10)$. X - 3)(x 10)$. X 2 7x - 30$ = $(x 10)(x - 3)$.
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There are many math homework helpers online; apart from tutorials and solved examples, students can get help from math tutors for a comprehensive lesson, covering every topic and concept. Irrespective of which option a student chooses, learning online is much more flexible and student-centered than any other method of learning. Solve $ sqrt{2x 9}$ $x$ = 13. Given: $ sqrt{2x 9}$ $x$ = 13. Sqrt{2x 9}$ = 13 - $x$. By squaring both side, we get. 2x 9 = (13 - x) 2$. 2x 9 = 169 x 2 - 26x$. X 2 - 28x 160 = 0$.
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