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rmandvikar.blogspot.com

RM

A blog about Algorithms and Data Structures

http://rmandvikar.blogspot.com/

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RM | rmandvikar.blogspot.com Reviews
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A blog about Algorithms and Data Structures
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1 labels algorithms
2 no comments
3 for f
4 f' return t
5 end left
6 0 & a right 1
7 use bit arithmetic
8 max a b
9 get all subarrays
10 older posts
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labels algorithms,no comments,for f,f' return t,end left,0 & a right 1,use bit arithmetic,max a b,get all subarrays,older posts,search this blog,loading,rmandvikar linkedin,rm stackoverflow,github,blog archive,contributors,rish mandvikar,list,labels,code
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RM | rmandvikar.blogspot.com Reviews

https://rmandvikar.blogspot.com

A blog about Algorithms and Data Structures

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1

RM: subarray with sum 0 in array

http://rmandvikar.blogspot.com/2015/08/subarray-with-sum-0-in-array.html

Thursday, August 06, 2015. Subarray with sum 0 in array. Example 1 3 -5 2 1 0 1. Naive approach. Get the longest subarray. Time: O(n 2) (a): maxstart = 0, maxend = -1 for i = 0, i. Maxend-maxstart: maxstart = i maxend = j if maxend = -1: return -1, -1 return maxstart, maxend. Better approach is to keep the running sum and a map of sum- i. If sum exists in map, then subarray is from map[sum] 1 to i. Get the longest subarray. Example a: 0 -1 1 0 sum: 0 -1 0 0 - - - - - - - -. Posted by Rish Mandvikar.

2

RM: all pairs in array that sum to k

http://rmandvikar.blogspot.com/2015/08/all-pairs-in-array-that-sum-to-k.html

Thursday, August 13, 2015. All pairs in array that sum to k. Example: k = 5 a : 1 3 4 5 6 7 2 2 -1 delta: 4 2 1 0 -1 -2 3 3 6 / delta = k - a[i] pairs: (1,4), (3,2), (3,2), (6,-1) k = 5 a: 3 3 2 3 delta: 2 2 3 2 pairs: (3,2), (3,2), (2,3). O(n) time, O(n) space (a, k): pairs = new map ncountmap = new for i = 0, i. Posted by Rish Mandvikar. Subscribe to: Post Comments (Atom). Simple template. Powered by Blogger.

3

RM: english phrase for integer

http://rmandvikar.blogspot.com/2015/08/english-phrase-for-integer.html

Wednesday, August 12, 2015. English phrase for integer. 999,999,999,999 - nine hundred ninety nine billion, nine hundred ninety nine million, nine hundred ninety nine thousand, nine hundred ninety nine. Divide the number into groups of 3 digits. Each group has a suffix as thousand, million, billion, etc. except the first. Within the group the phrasing is same. Hat tip to ctci]. Posted by Rish Mandvikar. Subscribe to: Post Comments (Atom). Simple template. Powered by Blogger.

4

RM: max of two integers, no compare operator or if else

http://rmandvikar.blogspot.com/2015/08/max-of-two-integers-no-compare-operator-or-if-else.html

Monday, August 10, 2015. Max of two integers, no compare operator or if else. For ve (and 0), msb is 0. For -ve, msb is 1. Returns a, when a b, a-b is ve, so a * 1 b * 0. Returns b, when b a, a-b is -ve, so a * 0 b * 1. 0 for ve, 1 for -ve, 0 for 0. msb(x): return (x 31) and 1 lsb(x): return x and 1 / returns 1 if ve, 0 if -ve, 1 if 0. / bit is 0 or 1 only ispositive(bit): return msb(bit) 1 / or msb(bit) &1. Bug max(a, b): return a * ispositive(a-b) b * ispositive(b-a). Hat tip to ctci]. Return 1 for ve,...

5

RM: minimal middle unsorted part of array

http://rmandvikar.blogspot.com/2015/08/minimal-middle-unsorted-part-of-array.html

Monday, August 10, 2015. Minimal middle unsorted part of array. Find the minimal middle unsorted part of array which if sorted would make the array sorted. The array consists of 3 parts left, middle, right. Initially left is the increasing sequence from beginning and right is the decreasing sequence from end. The left and right parts shrink till the following condition is met. Example l r 134558-58-4889 455-58-8 min:4 max:8 l r 123-2 2-3 min:2, max:3 l r 4-32-1 1-23-4 min:1, max:4. Hat tip to ctci].

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Thursday, August 13, 2015. All pairs in array that sum to k. Example: a : 1 3 4 5 6 7 2 -1 delta: 4 2 1 0 -1 -2 3 6 / delta = k - a[i] pairs: (1,4), (3,2), (6,-1). O(n) time, O(n) space (a, k): pairs = new set numbers = new / for indexs, use map as ntoi[a[i] = i for i = 0, i. Links to this post. Posted by Rish Mandvikar. Wednesday, August 12, 2015. Derive an unbiased function given a biased one. P(0) = 0.4. P(1) = 0.6. Derive f() such that. P(0) = 0.5. P(1) = 0.5. Links to this post. 0: groups.add(n ...

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