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Sagnik's WebLog

Friday, March 5, 2010. This is one interesting problem and I had some discussion about it with one of my classmates which gave a lot of insight to the problem. The problem can be found in Sipser 1.40. Let $NOPREFIX(A)= {w in A textrm{ no proper prefix of }w textrm{ is a member of }A }$, and $NOEXTEND(A)= {w in A w textrm{ is not the proper prefix of any member of }A }$. Show that the class of regular language is closed under these two operations. The question is whether $NOPREFIX(A)=NOEXTEND(A)$ or not&#...

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Sagnik's WebLog | soledadsagnik.blogspot.com Reviews
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Friday, March 5, 2010. This is one interesting problem and I had some discussion about it with one of my classmates which gave a lot of insight to the problem. The problem can be found in Sipser 1.40. Let $NOPREFIX(A)= {w in A textrm{ no proper prefix of }w textrm{ is a member of }A }$, and $NOEXTEND(A)= {w in A w textrm{ is not the proper prefix of any member of }A }$. Show that the class of regular language is closed under these two operations. The question is whether $NOPREFIX(A)=NOEXTEND(A)$ or not&#...
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1 sagnik's weblog
2 noprefix and noextend
3 1 scribelets
4 some tricky cfls
5 follows
6 guessed
7 accept
8 following
9 nondeterministically
10 reject
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Sagnik's WebLog | soledadsagnik.blogspot.com Reviews

https://soledadsagnik.blogspot.com

Friday, March 5, 2010. This is one interesting problem and I had some discussion about it with one of my classmates which gave a lot of insight to the problem. The problem can be found in Sipser 1.40. Let $NOPREFIX(A)= {w in A textrm{ no proper prefix of }w textrm{ is a member of }A }$, and $NOEXTEND(A)= {w in A w textrm{ is not the proper prefix of any member of }A }$. Show that the class of regular language is closed under these two operations. The question is whether $NOPREFIX(A)=NOEXTEND(A)$ or not&#...

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Sagnik's WebLog: February 2010

http://soledadsagnik.blogspot.com/2010_02_01_archive.html

Saturday, February 27, 2010. Today I found another interesting problem in Sipser ( refer to 1.59. The problem is the problem of synchronizing sequence, and is a "starred" problem! We are to find the upper bound of a k-state synchronizable DFA. Which we are to show as $k 3$). The definition of synchronizing sequence. Is somewhat intuitive. Let $M$ be a DFA and $h$ be a state of it called home . Synchronizing sequence for $M$ and. H$ is a string $s in Sigma *$, where $ delta(q,s)=h$ for every $q in Q$.

2

Sagnik's WebLog: Synchronizing Sequence

http://soledadsagnik.blogspot.com/2010/02/synchronizing-sequence.html

Saturday, February 27, 2010. Today I found another interesting problem in Sipser ( refer to 1.59. The problem is the problem of synchronizing sequence, and is a "starred" problem! We are to find the upper bound of a k-state synchronizable DFA. Which we are to show as $k 3$). The definition of synchronizing sequence. Is somewhat intuitive. Let $M$ be a DFA and $h$ be a state of it called home . Synchronizing sequence for $M$ and. H$ is a string $s in Sigma *$, where $ delta(q,s)=h$ for every $q in Q$.

3

Sagnik's WebLog: Shuffle and Perfect Shuffle

http://soledadsagnik.blogspot.com/2010/02/shuffle-and-perfect-shuffle.html

Thursday, February 25, 2010. Shuffle and Perfect Shuffle. These two problems from the book of Mike Sipser (1.41 and 1.42) need a little bit of discussion, for I guess these two are the most coveted problems in all university coursework. Question# 1.41 deals with shuffle. And question# 1.42 is an extension of shuffle. Let's look at the problem of perfect shuffle. First, then we can modify our answer for shuffle. For language $A$ and $B$, let the perfect shuffle. Q=Q A textrm{ x }Q B textrm{ x } {A,B }$.

4

Sagnik's WebLog: NoPrefix and NoExtend

http://soledadsagnik.blogspot.com/2010/03/noprefix-and-noextend.html

Friday, March 5, 2010. This is one interesting problem and I had some discussion about it with one of my classmates which gave a lot of insight to the problem. The problem can be found in Sipser 1.40. Let $NOPREFIX(A)= {w in A textrm{ no proper prefix of }w textrm{ is a member of }A }$, and $NOEXTEND(A)= {w in A w textrm{ is not the proper prefix of any member of }A }$. Show that the class of regular language is closed under these two operations. The question is whether $NOPREFIX(A)=NOEXTEND(A)$ or not&#...

5

Sagnik's WebLog: An Almost Irregular Regular Language!

http://soledadsagnik.blogspot.com/2010/02/almost-irregular-regular-language.html

Friday, February 26, 2010. An Almost Irregular Regular Language! This problem has its own class. The problem says,. Let $ Sigma= {0,1 }$ and let [D= {w w textrm{ contains an equal number of occurances of the substring }01 textrm{ and }10 } ] Thus $101 in D$ but $1010$ doesn't. Prove that $D$ is a regular language. Refer to Sipser 1.48. Another interesting problem which looks closely nonregular can be found in Sipser 1.44. The problem again deals with equal occurance, as follows:. Let $B$ and $C$. A rando...

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My Les Paul Experience | Sagnik's WebLog

https://sagnikm.wordpress.com/2010/03/10/my-les-paul-experience

March 10, 2010 /. My Les Paul Experience. Sorry for the long gap, I have been busy in developing my other blog (the technical one) in Blogspot. But today I came back with a freshly brewed experience of handling a Les Paul in a recent jamming session. I am not a good guitarist (which I have mentioned a countless number of times), worse with an electric guitar. In my entire life I have touched an electric guitar around four times, so that definitely doesn’t make me a guitar connoisseur! We started up with ...

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Sagnik's WebLog

Friday, March 5, 2010. This is one interesting problem and I had some discussion about it with one of my classmates which gave a lot of insight to the problem. The problem can be found in Sipser 1.40. Let $NOPREFIX(A)= {w in A textrm{ no proper prefix of }w textrm{ is a member of }A }$, and $NOEXTEND(A)= {w in A w textrm{ is not the proper prefix of any member of }A }$. Show that the class of regular language is closed under these two operations. The question is whether $NOPREFIX(A)=NOEXTEND(A)$ or not&#...

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