spmath90509.blogspot.com
Scribe Post for May 20, 2010
http://spmath90509.blogspot.com/2010/05/scribe-post-for-may-20-2010.html
This site belongs to the class of 9-05 at Sargent Park School any correspondence can be addressed to rbacke97@gmail.com. Scribe Post for May 20, 2010. Saturday, May 29, 2010. Hello there, 9-05! Circumference - The boundary of or distance around a circle. Diameter - The distance across a circle through its centre. Radius - A line segment joining the centre of a circle to the outside edge. The angles ABC is called a Central Angle. Central Angle - An angle form by two radii of a circle. If you flip it over ...
spmath90510.blogspot.com
905 MATH (2010): January 2011
http://spmath90510.blogspot.com/2011_01_01_archive.html
Friday, January 28, 2011. Binesi's Blog for January 28th 2011. Today in Class we took some notes. I was half awake and on the verge of collapsing, so I didn't quite get all of the information. I borrowed Hannah's notes so I figure about half of this scribe is accredited to her. For homework we have to do a Power Point Presentation. Put an example, non example, picture, and a definition. We also have to do 6.3 CYU #2, either the odd or even for practice, Apply (any 3), and extend any 2. Cm 2m, 413m, 819m,...
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905 MATH (2010): February 2011
http://spmath90510.blogspot.com/2011_02_01_archive.html
Monday, February 28, 2011. Noelle's Blog Post for Feb. 28th, 2011. What did we learn today? Turning a trinomial into a binomial:. Trinomial - - Binomial. How do you do it? To get from a trinomial to binomial you have to find the product of each term and seperate them into the two terms of a binomial. Here's the tricky part; The constants in your binomials must add up to the constant or coefficient in the middle term, but multiply to get the constant or coefficient in the last term of the trinomial. Homew...
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905 MATH (2010): September 2010
http://spmath90510.blogspot.com/2010_09_01_archive.html
Thursday, September 30, 2010. Kamille's Blog Post for September 30th. Today in math class, we went over the homework with the net of the diagram he drew for us yesterday. The net looks something like this:. Also we did a 3D diagram in an isometric dotted paper that looks something like this:. Then we did the went over one of the. On Page 29 on the math-book. What is the area of the surface that is against the ground? SA = 80( 60 20 30 20. SA = 2 [40 (60) 20 (30) ]. SA = 2 ( 2400 600 ). SA = 2 (3000).
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905 MATH (2010): Scribepost May 3, 2011
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Tuesday, May 3, 2011. Scribepost May 3, 2011. Today in Math, we continued on circle geometry. Basically, Backé taught us more on how to figure out the the angle of an inscribed angle by looking at its central angle. He also gave us words and diagrams that we need to know. First, he showed us something we should know already. Here are kinds of triangles according to sides. Are triangles with 3 equal sides, Isosceles Triangles. Have 2 equal sides, while Scalene Triangles. Have no sides equal. Other Cool Ma...
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905 MATH (2010): Jennifer's Post for April 25th, 2011
http://spmath90510.blogspot.com/2011/04/jennifers-post-for-april-25th-2011.html
Monday, April 25, 2011. Jennifer's Post for April 25th, 2011. We started on a new chapter on Inequalities so far in math class, Mr.Backe started us off with an equation plus we learned how to do a solution set for x. The one with the bracket in the middle is the Solution set. Pretty much it's like a word answer but in math form. We also did some other questions similar in class as well. Here's some photos of some of the questions we did in class and how I solve it. Thats All for now! Other Cool Math Sites.
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905 MATH (2010): March 2011
http://spmath90510.blogspot.com/2011_03_01_archive.html
Wednesday, March 23, 2011. Jem's Blog for March 22, 2011. So yesterday for math class our test was. Due to lack of understanding questions and how to solve them. Anyways, to help us understand the "hard" questions Mr.Backe went over questions with us, and made sure that we. What the questions mean, and how to solve them. Lets begin :. Solve what you can and need to first ). From here you can now cross multiply ). 2 ( 2x 8 ) = 9x 18. Now you solve what you can and need to again ). 4x - 16 = 9x 18. Next, w...
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905 MATH (2010): Jomari's Post for May 4, 2011
http://spmath90510.blogspot.com/2011/05/jomaris-post-for-may-4-2011.html
Wednesday, May 4, 2011. Jomari's Post for May 4, 2011. Today we learned about perpendicular bisectors. These are lines that bisect straight lines at 90°. Here's how to make one:. We made these bisectors for several chords. In a circle, we don't need to make crossed arcs on one side of the chord because of the center. After wards, we answered a problem involving bisectors. It was similar to this:. This is what we have to work with:. WE COULD USE THE PYTHAGORAS THEOREM TO FIND B. 178; b²=c². 8730; b ².
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905 MATH (2010): Jem's Post for April 5, 2011
http://spmath90510.blogspot.com/2011/04/jems-post-for-april-5-2011.html
Tuesday, April 5, 2011. Jem's Post for April 5, 2011. Hi guys, if i haven't welcomed you guys yet . welcome back! Right when class started Mr.Backe reminded us about everything due. Then everyone was busy. Chapter 7 ; Self Assessment. Problems of the Week # 1, 2, 3. Eg ; For #3 we had a little lesson on the Fibonacci sequence like Emmanuel explained "The Fibonacci sequence, is a pattern. 1,1,2,3,5,8 . etc". Chapter 8; Foldable ( Attach your chapter 8 Self Assessment to Show You Know). Area of a circle.
spmath90510.blogspot.com
905 MATH (2010): April 2011
http://spmath90510.blogspot.com/2011_04_01_archive.html
Monday, April 25, 2011. Jennifer's Post for April 25th, 2011. We started on a new chapter on Inequalities so far in math class, Mr.Backe started us off with an equation plus we learned how to do a solution set for x. The one with the bracket in the middle is the Solution set. Pretty much it's like a word answer but in math form. We also did some other questions similar in class as well. Here's some photos of some of the questions we did in class and how I solve it. Thats All for now! Here's most of it.