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Sunday, June 24, 2012. Political candidate estimates that 30% of the voters in his party favor his proposed tax reform bill. If there are 400 people at a rally, find the probability that at least 100 favor his tax bill. Wednesday, January 26, 2011. Let X be the incomes of families. We have P(z Z 0)=0.32, then z = -0.92. Hence, the cut-off income is about $18840. Tuesday, January 25, 2011. Let X be the car prices. Hence, the minimum price is. And maximum price is. Student takes a 10-question, true/false e...

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problem-solution statistics | statisticsproblems.blogspot.com Reviews

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Sunday, June 24, 2012. Political candidate estimates that 30% of the voters in his party favor his proposed tax reform bill. If there are 400 people at a rally, find the probability that at least 100 favor his tax bill. Wednesday, January 26, 2011. Let X be the incomes of families. We have P(z Z 0)=0.32, then z = -0.92. Hence, the cut-off income is about $18840. Tuesday, January 25, 2011. Let X be the car prices. Hence, the minimum price is. And maximum price is. Student takes a 10-question, true/false e...

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problem-solution statistics | statisticsproblems.blogspot.com Reviews

https://statisticsproblems.blogspot.com

Sunday, June 24, 2012. Political candidate estimates that 30% of the voters in his party favor his proposed tax reform bill. If there are 400 people at a rally, find the probability that at least 100 favor his tax bill. Wednesday, January 26, 2011. Let X be the incomes of families. We have P(z Z 0)=0.32, then z = -0.92. Hence, the cut-off income is about $18840. Tuesday, January 25, 2011. Let X be the car prices. Hence, the minimum price is. And maximum price is. Student takes a 10-question, true/false e...

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statisticsproblems.blogspot.com

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problem-solution statistics: Problem Solution 9

http://statisticsproblems.blogspot.com/2011/01/problem-solution-9.html

Wednesday, January 26, 2011. An advertising company plans to market a product to low-income families. A study states that for a particular area, the average income per family is $ 24596 and the standard deviation is $6256. If the company plans to target the bottom 18% of the families based on income, find the cut-off income. Assume the variable is normally distributed. Let X be the incomes of families. We have P(z Z 0)=0.32, then z = -0.92. Hence, the cut-off income is about $18840.

2

problem-solution statistics: Problem solution 7

http://statisticsproblems.blogspot.com/2011/01/problem-solution-7.html

Tuesday, January 25, 2011. Student takes a 10-question, true/false examination and guesses on each question. Find the probability of passing if the lowest passing grade is 6 correct out of 10. Let X be the number of questions that the student guesses correct. He passes the examination if X is greater than or equal to 6. X follows binomial distribution with n = 10 and the probability of success is 0.5. The goal is to find P(X =6). February 19, 2011 at 12:20 AM. Why probability of success is 0.5?

3

problem-solution statistics: January 2011

http://statisticsproblems.blogspot.com/2011_01_01_archive.html

Wednesday, January 26, 2011. An advertising company plans to market a product to low-income families. A study states that for a particular area, the average income per family is $ 24596 and the standard deviation is $6256. If the company plans to target the bottom 18% of the families based on income, find the cut-off income. Assume the variable is normally distributed. Let X be the incomes of families. We have P(z Z 0)=0.32, then z = -0.92. Hence, the cut-off income is about $18840. And maximum price is.

4

problem-solution statistics: Problem solution 6

http://statisticsproblems.blogspot.com/2011/01/problem-solution-6.html

Sunday, January 23, 2011. A study of the lines at the checkout registers of Safeway Supermarket revealed that, during a certain period at the rush hour, the number of customers waiting averaged four. What is the probability that during that period:. A) No customer were waiting? B) Four customers were waiting? C) For or fewer were waiting? D) Four or more were waiting? Let X be the number of customers waiting during the rush hour, then X follows Poisson distribution with lambda equal to 4. Hence,.

5

problem-solution statistics: Problem solution 8

http://statisticsproblems.blogspot.com/2011/01/problem-solution-8.html

Tuesday, January 25, 2011. An automobile dealer finds that the average price of a previously owned vehicle is $8256. He decides to sell cars that will appeal to the middle 60% of the market in terms of price. Find the maximum and minimum prices of the cars and dealer will sell. The standard deviation is $1150, and the variable is normally distributed. Let X be the car prices. We have 2*P(0 Z z)=0.6, then P(0 Z z)=0.3, it implies that z = 0.84 (from the table). Hence, the minimum price is.

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problem-solution statistics

Sunday, June 24, 2012. Political candidate estimates that 30% of the voters in his party favor his proposed tax reform bill. If there are 400 people at a rally, find the probability that at least 100 favor his tax bill. Wednesday, January 26, 2011. Let X be the incomes of families. We have P(z Z 0)=0.32, then z = -0.92. Hence, the cut-off income is about $18840. Tuesday, January 25, 2011. Let X be the car prices. Hence, the minimum price is. And maximum price is. Student takes a 10-question, true/false e...

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