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Fun with Mathematics

Thursday, June 19, 2014. More about Pythagorean triples. More about Pythagorean triples. Must be equal to the number digit of c. It requires that the number digit of either a. Must be 9 so that the number digit of the remaining square in one side will ne equal to the number digit of c. All numbers which are multiples of three will give number digit 9 for its square. Hence either ‘a’ or ‘b’ must be a multiple of three.If ‘a’ is multiple of three, then a. Will be divisible by three.It means that c. 3x 4y =...

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Thursday, June 19, 2014. More about Pythagorean triples. More about Pythagorean triples. Must be equal to the number digit of c. It requires that the number digit of either a. Must be 9 so that the number digit of the remaining square in one side will ne equal to the number digit of c. All numbers which are multiples of three will give number digit 9 for its square. Hence either ‘a’ or ‘b’ must be a multiple of three.If ‘a’ is multiple of three, then a. Will be divisible by three.It means that c. 3x 4y =...

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fun with mathematics,and b,or b,posted by,meyyappa meyyappan,no comments,email this,blogthis,share to twitter,share to facebook,share to pinterest,where,irreducible triple 7,new relations,integers,right angled triangle,we get,ie c,2 since,must be even

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Fun with Mathematics | thavakkai.blogspot.com Reviews

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Thursday, June 19, 2014. More about Pythagorean triples. More about Pythagorean triples. Must be equal to the number digit of c. It requires that the number digit of either a. Must be 9 so that the number digit of the remaining square in one side will ne equal to the number digit of c. All numbers which are multiples of three will give number digit 9 for its square. Hence either ‘a’ or ‘b’ must be a multiple of three.If ‘a’ is multiple of three, then a. Will be divisible by three.It means that c. 3x 4y =...

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Fun with Mathematics

http://thavakkai.blogspot.com/2014/06/pythagorean-triples-withgiven-endings_17.html

Tuesday, June 17, 2014. Pythagorean triples with given endings. Here is yet another method to identify Pythagorean triples with given endings. The Pythagorean triples (a,b,c) satisfy the relation a. Let us try to find a series of Phythagorean triples ending with 3,4 and 5 (greatest). The most general form for this set is. It gives a condition for the suitable values of x,y,and z.- 5(x. 3x 4y = 5z(z 1). The other requirement for the Pythagorean triples is a b = c 2. When α = 1. Y=4 gives (3,4,5).

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Fun with Mathematics: February 2013

http://thavakkai.blogspot.com/2013_02_01_archive.html

Sunday, February 24, 2013. Magical properties of cubes-4. Magical properties of cubes-4. We find some regularities in the divisibility of cube numbers by different divisors, where the remainder has cyclic variation. When n. Is divided by 2, there is no remainder for all even n, and 1 for all odd n.The remainder varies cyclically 1 and 0. When divided by 3, the remainder varies repeatedly in a cycle 1,2,0 for. Saturday, February 23, 2013. Magical power of cubes-3. Magical properties of cubes -3. We know t...

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Fun with Mathematics: June 2013

http://thavakkai.blogspot.com/2013_06_01_archive.html

Thursday, June 20, 2013. In a newly constructed apartment, a lab our fixed door numbers for all the 100 houses built therein ,with a set of single number metal plates.How many single number metal plates with number 0,1,2,3,4….9 are required? Single-9,double (from10 to 99)- 90x2 = 180 Triple -1 ,1x3 =3. RANGE 0 1 2 3 4 5 6 7 8 9. 1-10 1 2 1 1 1 1 1 1 1 1. 11-20 1 10 2 1 1 1 1 1 1 1. 21-30 1 1 10 2 1 1 1 1 1 1. 31-40 1 1 1 10 2 1 1 1 1 1. 41-50 1 1 1 1 10 2 1 1 1 1. 51-60 1 1 1 1 1 10 2 1 1 1.

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Fun with Mathematics: November 2011

http://thavakkai.blogspot.com/2011_11_01_archive.html

Friday, November 18, 2011. One more general proof for Fermat's Last theorem. The equal power relation in the form a n b n = c n cannot be existing with integral values for a,b and c and for any value of n except 1 and 2. This relation ,if it exists ,can then be expressed in the Pythagorean form as. A n/2) 2 (b n/2) 2 = (c n/2) 2. Where the Pythagorean triple is a power of numbers. All Pythagorean triples (x,y,z) must satisfy a condition xy = 2n(z n). Ab(ab) 1/2 = 2n [c(c) 1/2 n]. Z 2 -y 2= x 2. 1In all P...

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Fun with Mathematics: June 2012

http://thavakkai.blogspot.com/2012_06_01_archive.html

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Fun with Mathematics

Thursday, June 19, 2014. More about Pythagorean triples. More about Pythagorean triples. Must be equal to the number digit of c. It requires that the number digit of either a. Must be 9 so that the number digit of the remaining square in one side will ne equal to the number digit of c. All numbers which are multiples of three will give number digit 9 for its square. Hence either ‘a’ or ‘b’ must be a multiple of three.If ‘a’ is multiple of three, then a. Will be divisible by three.It means that c. 3x 4y =...

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