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汪小祯 - Nine's Blog

汪小祯 - Nines Blog. 448 Find All Numbers Disappeared in an Array. Given an array of integers where 1 a[i] n (n = size of array), some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space. Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.

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汪小祯 - Nines Blog. 448 Find All Numbers Disappeared in an Array. Given an array of integers where 1 a[i] n (n = size of array), some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space. Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.

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汪小祯 - Nine's Blog | wxz.name Reviews

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汪小祯 - Nines Blog. 448 Find All Numbers Disappeared in an Array. Given an array of integers where 1 a[i] n (n = size of array), some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space. Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.

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汪小祯 - Nine's Blog | 136. Single Number

http://www.wxz.name/2017/01/09/LeetCode136

汪小祯 - Nines Blog. Given an array of integers, every element appears twice except for one. Find that single one. Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Class Solution { public: int singleNumber(vector int &nums) { int num = 0; for(int i=0;i nums.size();i ) { num = num nums[i]; } return num; } };. 可以得到A A=0 A A 1=1 A B A B C=C这样.

2

汪小祯 - Nine's Blog | 344. Reverse String

http://www.wxz.name/2017/01/09/LeetCode344

汪小祯 - Nines Blog. Write a function that takes a string as input and returns the string reversed. Given s = hello , return olleh . Subscribe to see which companies asked this question. Class Solution { public: string reverseString(string s) { string a=s; int j=0; for (int i=s.size()-1;i =0;i- ,j ) { a[j]=s[i]; } return a; } };. Class Solution { public: string reverseString(string s) { int i = 0, j = s.size() - 1; while(i j){ swap(s[i ], s[j- ]); } return s; } };.

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汪小祯 - Nine's Blog | 我的开源项目

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汪小祯 - Nine's Blog | 463. Island Perimeter

http://www.wxz.name/2017/01/11/LeetCode463

汪小祯 - Nines Blog. Explanation: The perimeter is the 16 yellow stripes in the image below:. Class Solution { public: int islandPerimeter(vector vector int and grid) { if (grid.size()= 0) return 0; int count=0; int round=0; for (int i=0; i grid.size(); i ) { for (int j=0; j grid[0].size(); j ) { if(grid[i][j]= 1) { count ; if(i! Gridsize()-1& grid[i 1][j]= 1) round ; if(j! Grid[0].size()-1& grid[i][j 1]= 1) round ; } } } return count*4-round*2; } };. If(grid[i 1][j]= 1) round ; if(grid[i][j 1]= 1) round ;.

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汪小祯 - Nine's Blog | Categories

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汪小祯 - Nines Blog. 405 Convert a Number to Hexadecimal. 349 Intersection of Two Arrays. 453 Minimum Moves to Equal Array Elements. 389 Find the Difference. 448 Find All Numbers Disappeared in an Array.

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Codeforces Round #369 (Div. 2) | 火药

http://gunpowder.net.cn/archives/423

Go big or go home. 八月 30, 2016. Codeforces Round #369 (Div. 2). A Bus to Udayland. B Chris and Magic Square. Tmp) { printf("-1 n"); return 0; } } for (i = 1; i = n; i) { sum = 0; for (j = 1; j = n; j) sum = a[j][i]; if (sum! Tmp) { printf("-1 n"); return 0; } } sum = 0; for (i = 1; i = n; i) { sum = a[i][i]; } if (sum! Tmp) { printf("-1 n"); return 0; } sum = 0; for (i = 1; i = n; i) { sum = a[i][n 1-i]; } if (sum! Tmp) { printf("-1 n"); return 0; } printf("%lld n", a[x][y]); return 0; }. 发表在 FFT 与 NTT.

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2016 Multi-University Training Contest 4 总结 | 火药

http://gunpowder.net.cn/archives/375

Go big or go home. 七月 29, 2016. 2016 Multi-University Training Contest 4 总结. 这场来说是打的不错的，不过也有一点小小瑕疵，比如 1001 没有看到取模 WA 了一发。进行一遍 KMP 预处理一下匹配的信息，然后做一遍 DP 就好了。 Case #%d: %d n". 主要是先容斥，容斥的过程中用中国剩余定理算出数量，在做 CRT 的时候会爆 long long，需要用按位相乘处理一下。 Define LL long long. 1010 The All-purpose Zero. 遇到 0 不处理，最后把答案数加上总的 0 的个数即可。 Case #%d: %d n". 1011 Where Amazing Happens. 2016 Multi-University Training Contest 3 总结. 2016 Multi-University Training Contest 5 总结 →. Ubuntu 下搭建 masm 汇编环境. Codeforces Round #369 (Div. 2).

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汇编 | 火药

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Go big or go home. 十一月 1, 2016. Ubuntu 下搭建 masm 汇编环境. 搭建 DOS 环境这里使用作为虚拟环境。 Ubuntu 下搭建 masm 汇编环境. 2016 ACM/ICPC Asia Regional Dalian Online 总结. Codeforces Round #369 (Div. 2). AIM Tech Round 3 (Div. 2). 2016中国大学生程序设计竞赛 - 网络选拔赛总结. Codeforces Round #367 (Div. 2). 2016 Multi-University Training Contest 6 - 8 总结. 2016 Multi-University Training Contest 5 总结. 发表在 FFT 与 NTT. 发表在 AIM Tech Round 3 (Div. 2). 发表在 FFT 与 NTT. Go big or go home.

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2016 ACM/ICPC Asia Regional Dalian Online 总结 | 火药

http://gunpowder.net.cn/archives/426

Go big or go home. 九月 11, 2016. 2016 ACM/ICPC Asia Regional Dalian Online 总结. 1002 Different GCD Subarray Query. FOJ 2244 原题，从区间里的 GCD 个数不会超过. 按照答案写出的做法，虽然是错的，但还是A了，说明标程也是错的啊赛后就被清华爷 Hack 了。 1007 Friends and Enemies. Include cstdio #include cstring #include cstdlib #include cmath #include algorithm using namespace std; long long n, m; int main() { while ( scanf("%lld%lld", &m, &n) { if ( m*m/4) = n) printf("T n"); else printf("F n"); } return 0; }. Panend() {q.push(*it); it;} while(! NULL) size =ch[1]- ...

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FFT 与 NTT | 火药

http://gunpowder.net.cn/archives/430

Go big or go home. 九月 27, 2016. 0) t = i; } for (i = t; i = 0; - i) printf("%lld", ans[i]); printf(" n"); return 0; }. Define clr( a , x ) memset ( a , x , sizeof a ). Define cpy( a , x ) memcpy ( a , x , sizeof a ). 0) t = i; } for (i = t; i = 0; - i) printf("%lld", a[i]); printf(" n"); return 0; }. 2016 ACM/ICPC Asia Regional Dalian Online 总结. Ubuntu 下搭建 masm 汇编环境 →. 2 thoughts on “ FFT 与 NTT. Ubuntu 下搭建 masm 汇编环境. 2016 ACM/ICPC Asia Regional Dalian Online 总结. Codeforces Round #369 (Div. 2).

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火药 | Go big or go home - Part 2

http://gunpowder.net.cn/page/2

Go big or go home. 七月 29, 2016. 2016 Multi-University Training Contest 4 总结. 这场来说是打的不错的，不过也有一点小小瑕疵，比如 1001 没有看到取模 WA 了一发。七月 28, 2016. 2016 Multi-University Training Contest 3 总结. 这次多校一共出了 5 题,整体上来说是很满意的。因为其中有 4 题是一遍 AC，没有花太多的时间去纠结。七月 22, 2016. 2016 Multi-University Training Contest 2 总结. 主要问题出在两点 1. 有些智商题建模比较慢 […]. 五月 2, 2016. 三月 25, 2016. 三月 19, 2016. 二月 29, 2016. 二月 29, 2016. 附言不得不吐槽POJ，注意这种题目的printf控制符一定要注意，还有四舍五入可能会带来的误差，而且doub […]. 二月 17, 2016. 代码 [cray […]. 二月 16, 2016. 038; […]. 发表在 FFT 与 NTT.

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2016 Multi-University Training Contest 5 总结 | 火药

http://gunpowder.net.cn/archives/384

Go big or go home. 八月 3, 2016. 2016 Multi-University Training Contest 5 总结. 我的做法主要是 DP ，每次选取中间要试探的数进行 DP ，并且先离线都预处理好。 1003 Divide the Sequence. 1012 World is Exploding. 2016 Multi-University Training Contest 4 总结. 2016 Multi-University Training Contest 6 - 8 总结 →. 2 thoughts on “ 2016 Multi-University Training Contest 5 总结. Ubuntu 下搭建 masm 汇编环境. 2016 ACM/ICPC Asia Regional Dalian Online 总结. Codeforces Round #369 (Div. 2). AIM Tech Round 3 (Div. 2). 2016中国大学生程序设计竞赛 - 网络选拔赛总结. 发表在 FFT 与 NTT. 发表在 FFT 与 NTT.

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欧泥酱 | 火药

http://gunpowder.net.cn/archives/author/admin

Go big or go home. 三月 2, 2017. 十一月 1, 2016. Ubuntu 下搭建 masm 汇编环境. 搭建 DOS 环境这里使用作为虚拟环境。九月 27, 2016. FFT 快速傅里叶变换 51Nod 1027. 0) t = i; } for (i = t; i = 0; - i) printf("%lld", ans[i]); printf(" n"); return 0; }. Define clr( a , x ) memset ( a , x , sizeof a ). Define cpy( a , x ) memcpy ( a , x , sizeof a ). 九月 11, 2016. 2016 ACM/ICPC Asia Regional Dalian Online 总结. 八月 30, 2016. Codeforces Round #369 (Div. 2). 恭喜婷巨上紫这场打的还是不错的，还是 4 题，按这个节奏也快能上紫了。 A Bus to U […]. 八月 25, 2016. AIM Tech Round 3 (Div. 2).

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火药 | Go big or go home - Part 3

http://gunpowder.net.cn/page/3

Go big or go home. 二月 14, 2016. 尾声 0080 春 SIDE-6终战后从某处传来了孩子们无忧无虑而开朗的笑声。二月 14, 2016. 第三章口袋里的战争嗯呼哼呼、嗯呼哼呼、嗯呼哼呼、呼呼、呼呼两肩挂着二挺机枪，眼光锐利的走在地下隧道的前锋 […]. 二月 14, 2016. 第二章渡过河流穿过森林然后呢，我就扑向了那个吉翁兵，对方虽然拿着枪，不过我就这样子，把它打掉了亚尔配合 […]. 二月 14, 2016. 第一章离战场还有多少里咻、啾啾咻噜咻噜、轰咚嗫着嘴而小声地发出投射飞弹的风驰掣的声音，亚尔以手臂围住 […]. 二月 14, 2016. 序幕 0079 冬北极海深处将如同狂风沙似的杂讯烙印在他的眼瞳之后，那面显像幕把一片泛青的白色，在画面中投 […]. 二月 12, 2016. 二月 7, 2016. 新春快乐祝大家新春快乐猴年大吉给大家拜年啦. 二月 3, 2016. 正题理解树状数组需要理解前缀和或者分治这种 […]. 二月 2, 2016. 二月 1, 2016. CF621E]Wet Shark and Blocks.

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汪小祯 - Nine's Blog

汪小祯 - Nines Blog. 448 Find All Numbers Disappeared in an Array. Given an array of integers where 1 a[i] n (n = size of array), some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this array. Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space. Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.

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Seit Frühjahr 2014 ist Wen Xiao Zheng Solobratscher. Beim Symphonieorchester des Bayerischen Rundfunks. Der in China geborene Zheng zählt zu den. Besten Violonisten seiner Generation. Preisen ausgestattet unter anderem der 2. Preis beim. ARD-Wettbewerb und Publikumspreis (der 1. wurde nicht. Vergeben) wurde er 2010 von der Konzertgesellschaft. München mit dem August-Everding-Preis ausgezeichnet. 8211; musikerlebnis.de. 2017 Wen Xiao Zheng.

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