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日月卦長的解題紀錄

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). 2007-2008 Summer Petrozavodsk Camp, Japanese Contest ] A. Reading Brackets in English. 題目在這裡: http:/ codeforces.com/gym/100963. S Longrightarrow list ; E. S Longrightarrow list ; L. L Longrightarrow E ; L. Size t i= 0.

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日月卦長的解題紀錄 | sunmoon-coding.blogspot.com Reviews

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Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{#1} ). 2007-2008 Summer Petrozavodsk Camp, Japanese Contest ] A. Reading Brackets in English. 題目在這裡: http:/ codeforces.com/gym/100963. S Longrightarrow list ; E. S Longrightarrow list ; L. L Longrightarrow E ; L. Size t i= 0.

<META> KEYWORDS

1 日月卦長的解題紀錄

2 latex預處理

3 這裡我把給的語法轉化成形式文法，如下

4 e longrightarrow t

5 e longrightarrow s

6 首先把形式文法轉乘cnf表達式

7 接著就可以跑cyk演算法了

8 include

9 bits/stdc h

10 using namespace

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日月卦長的解題紀錄,latex預處理,這裡我把給的語法轉化成形式文法，如下,e longrightarrow t,e longrightarrow s,首先把形式文法轉乘cnf表達式,接著就可以跑cyk演算法了,include,bits/stdc h,using namespace,std;,enum,p{ / symbol,struct,cnf{,inline void,cnf init {,p num ;,bool,cyk {,memset dp i i 0,sizeof,dp i i ;

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日月卦長的解題紀錄 | sunmoon-coding.blogspot.com Reviews

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Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). 2007-2008 Summer Petrozavodsk Camp, Japanese Contest ] A. Reading Brackets in English. 題目在這裡: http:/ codeforces.com/gym/100963. S Longrightarrow list ; E. S Longrightarrow list ; L. L Longrightarrow E ; L. Size t i= 0.

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日月卦長的解題紀錄: [ UVA ] 1298 - Triathlon

http://sunmoon-coding.blogspot.com/2015/12/uva-1298-triathlon.html

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). UVA ] 1298 - Triathlon. Https:/ uva.onlinejudge.org/index.php? 假設比賽總長度為1，其中游泳長度x，自行車長度y，賽跑長度1-x-y，則選手i打敗選手j的條件是：. X/v[i] y/u[i] (1-xy)/w[i] x/v[j] y/u[j] (1-xy)/w[j]. 因為數字很小且題目要求精度，所以把A、B、C都乘上10000. X*bx y*b.y;. N,v[m...

2

日月卦長的解題紀錄: 十月 2016

http://sunmoon-coding.blogspot.com/2016_10_01_archive.html

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). 2007-2008 Summer Petrozavodsk Camp, Japanese Contest ] A. Reading Brackets in English. 題目在這裡: http:/ codeforces.com/gym/100963. S Longrightarrow list ; E. S Longrightarrow list ; L. L Longrightarrow E ; L. Size t i= 0.

3

日月卦長的解題紀錄: [ codeforces ] ACM ICPC 2015–2016, Northeastern European Regional J Jump

http://sunmoon-coding.blogspot.com/2016/01/acm-icpc-20152016-northeastern-european-J.html

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). Codeforces ] ACM ICPC 2015–2016, Northeastern European Regional J Jump. 互動題，猜字串遊戲，輸入n表示字串長度，你要輸出一個字串給他. N =1000，你要在n 500次內猜出他的字串是什麼. 設s[0]屬於A，對於s[1] s[n-1]，把他們分別跟s[0]取not，假設現在是第i個字元. C 用cout.flush();.

4

日月卦長的解題紀錄: 二月 2016

http://sunmoon-coding.blogspot.com/2016_02_01_archive.html

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). Http:/ codingsimplifylife.blogspot.tw/2016/02/ioi-camp-judge-37 4.html. CDQ分治不會寫，所以就用老派的kd tree去解吧，這裡提供兩種寫法:. 第一種寫法是動態的將點進行插入，因為必須要做到動態的插入操作，而一般kd tree不能用旋轉的方式來平衡，所以利用替罪羊樹的概念來平衡。(3.10s). Using namespace std;. Xd[k] u-...

5

日月卦長的解題紀錄: [ UVA ] 741 - Burrows Wheeler Decoder

http://sunmoon-coding.blogspot.com/2016/01/uva-741-burrows-wheeler-decoder.html

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). UVA ] 741 - Burrows Wheeler Decoder. Https:/ uva.onlinejudge.org/index.php? P;cin s p;){. J n; j)a[j]=s[j] a[j];. Sort(a,a n);. 訂閱：張貼留言 (Atom). Codeforces ] Round #340 (Div. 2) E. XOR and Favo.

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日月卦長的解題紀錄

Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). 2007-2008 Summer Petrozavodsk Camp, Japanese Contest ] A. Reading Brackets in English. 題目在這裡: http:/ codeforces.com/gym/100963. S Longrightarrow list ; E. S Longrightarrow list ; L. L Longrightarrow E ; L. Size t i= 0.

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