sunmoon-smc.com
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Lee Chang-hyoug
387-6 Ojeong-dong●●●●●●●●●●●●●●●●●g-gu, GYEONGGI-DO
Bu●●on , 421170
KOREA, REPUBLIC OF
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Lee Chang-hyoug
387-6 Ojeong-dong●●●●●●●●●●●●●●●●●g-gu, GYEONGGI-DO
Bu●●on
KOREA, REPUBLIC OF
View this contact
Lee Chang-hyoug
387-6 Ojeong-dong●●●●●●●●●●●●●●●●●g-gu, GYEONGGI-DO
Bu●●on
KOREA, REPUBLIC OF
View this contact
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日月卦長的解題紀錄
Newcommand{ ord}[1]{ mathcal{O} left(#1 right)} newcommand{ abs}[1]{ lvert #1 rvert} newcommand{ floor}[1]{ lfloor #1 rfloor} newcommand{ ceil}[1]{ lceil #1 rceil} newcommand{ opord}{ operatorname{ mathcal{O} } newcommand{ argmax}{ operatorname{arg ,max} newcommand{ str}[1]{ texttt{"#1"} ). 2007-2008 Summer Petrozavodsk Camp, Japanese Contest ] A. Reading Brackets in English. 題目在這裡: http:/ codeforces.com/gym/100963. S Longrightarrow list ; E. S Longrightarrow list ; L. L Longrightarrow E ; L. Size t i= 0.
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Fast matrix power ] 矩陣快速冪. 對於一些DP題，我們可以把它轉變成矩陣乘法的狀態轉移，例如 費波那契數列. 來加速。像是求費式數列的第n項，當n很大的時候根本不能用線性的解法，而利用矩陣快速冪可以在O(logn)的時間內解出。 Matrix 2d &b) const. Matrix 2d c;. Cm[i][j] =m[i][k]*b.m[k][j];. Matrix 2d c,a=* this. I n; i)c.m[i][i]= 1. Matrix 2d T,n &b) const. Matrix 1d c;. Cm[i] =m[j]*b.m[j][i];. 對於一些詢問區間答案的資料結構題，我們已經知道了區間[l,r]的答案，且能在極少的時間( O(1) or O(logN) )內得到區間[l 1,r]、[l-1,r]、[l,r 1]、[l,r-1]的答案，題目也准許離線，只要滿足這些性質就可以使用莫隊。 首先我們須將所有詢問記錄下來，將序列分成sqrt(n)塊，找出每筆詢問l所在的塊，每塊內r由小排到大. L,r,i,block;. Q[i]l,&q[i].r);.
